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horrorfan [7]
3 years ago
14

Help please #12 Solve using factoring

Mathematics
2 answers:
Serga [27]3 years ago
5 0

(R-2)x(r+2) that what I think it is

zimovet [89]3 years ago
5 0

You have to use the sum/difference formula

(a+b)(a-b)=a^2-b^2

In your case, r^2-4 is a difference of squares, so it can be factored with the sum and difference of the roots:

r^2-4 = (r+2)(r-2)

So, we have

r^2-4 = 0 \iff (r+2)(r-2) = 0

A multiplication is zero if and only if one of the factors is zero, so we have

(r+2)(r-2) = 0 \iff r+2=0\ \lor\ r-2=0 \iff r=-2\ \lor\ r=2

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40%

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Scrat [10]

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: State the number of outcomes possible for three tossing of a coin

Since a coin has two possible outcomes and is tossed three times, the total outcomes will be:

\begin{gathered} 2^3=8 \\ 8\text{ outcomes} \end{gathered}

STEP 2: Find the number of sample spaces for the three tosses

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Hence, the answers are given as:

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\lbrace HHH,HHT,HTH,HTT,THH,THT,TTH,TTT\rbrace

The event that the second toss is tails:

\lbrace HTH,HTT,TTH,TTT\rbrace

4 0
1 year ago
Plzz help me to find coefficient in binomial theorem (25 points)
Viefleur [7K]

<em>Denote x2 by y. </em>

<em>  </em>

<em>(x2-3)7=(y-3)7 </em>

<em>  </em>

<em>This is a binomial expansion in y, and you want the coefficient of y4 because y4=x8 </em>

<em>  </em>

<em>You have 7 terms of (y-3) in (y-3)7.  To get the fourth power of y, you need to choose y from four of the terms.  The number of ways you can do this is the combinations of 7 things taken 4 at a time.  This is: </em>

<em>  </em>

<em>7!/(4!3!)=35</em>

<em />

<em>So, the coefficient of x8 in the given expansion will be 210.</em>

<em>HOPE IT HELPS</em>

<em>THANK YOU </em>

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stepladder [879]

Answer:

178.3 mm²

Explanation:

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3 years ago
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