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Sergio [31]
3 years ago
7

Find dy/dx. x^2y+xy^2=6

Mathematics
1 answer:
AfilCa [17]3 years ago
3 0
We are asked to evaluate dx/dy of the function x^2y+xy^2=6
we use implicit differentiation here:
2xy dx + 2xy dy = 0we can cancel 2xy from both terms in the left-hand side such that what is left is  dx/dy = 0 
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Answer:

37c

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6c+(7c+7c)+8c+9c

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37c

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The length of a DNA nucleotide building block is about 1 nanometer, or 0.000000001 meters. Fill in the blank to write this numbe
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Step-by-step explanation:

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Step-by-step explanation:

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Use the given transformation x=4u, y=3v to evaluate the integral. ∬r4x2 da, where r is the region bounded by the ellipse x216 y2
exis [7]

The Jacobian for this transformation is

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dA = dx\,dy = 12 \, du\,dv

Then the integral becomes

\displaystyle \iint_{R'} 4x^2 \, dA = 768 \iint_R u^2 \, du \, dv

where R' is the unit circle,

\dfrac{x^2}{16} + \dfrac{y^2}9 = \dfrac{(4u^2)}{16} + \dfrac{(3v)^2}9 = u^2 + v^2 = 1

so that

\displaystyle 768 \iint_R u^2 \, du \, dv = 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2 \, du \, dv

Now you could evaluate the integral as-is, but it's really much easier to do if we convert to polar coordinates.

\begin{cases} u = r\cos(\theta) \\ v = r\sin(\theta) \\ u^2+v^2 = r^2\\ du\,dv = r\,dr\,d\theta\end{cases}

Then

\displaystyle 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2\,du\,dv = 768 \int_0^{2\pi} \int_0^1 (r\cos(\theta))^2 r\,dr\,d\theta \\\\ ~~~~~~~~~~~~ = 768 \left(\int_0^{2\pi} \cos^2(\theta)\,d\theta\right) \left(\int_0^1 r^3\,dr\right) = \boxed{192\pi}

3 0
2 years ago
-11-2+3(4*6^2/(-9))]
Lelechka [254]

Answer:

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Step-by-step explanation:

get a calculator and type it

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