The reason you can only compare the numerators is because the denominators are the same- leaving little comparison to really make. The numerators will determine which fraction is greater or smaller.
Ex. 4/5 or 3/5
which is greater? Which is smaller?
It can be seen that the denominators are the same, now finally comparing the numerators will answer both questions.
please vote my answer brainliest. thanks!
Answer:
35+28=63
Step-by-step explanation:
hope this helps
Any of 9's multiples besides 9 and 18 will work.
So: 27, 35, 45, 54 ,63, 72, 81, 90, 99, 108, 117, 126, 135, and so on
Interesting question. Good to know for computer science.
Suppose you have a function like
an = 3x - 2 Try the first couple
a1 = 3(1) - 2
a1 = 3 - 2
a1 = 1
a2 = 3(2) - 2
a2 = 6 - 2
a2 = 4 So each term differs by 3
a2 - a1 = 3
an = a_(n - 1) + 3
a3 = a2 + 3
a3 = 4 + 3
a3 = 7
a4 = a3 + 3
a4 = 7 + 3
a4 = 10
a5 = a4+ 3
a5 = 10 + 3
a5 = 13
I'll do one more and then check it.
a6 = a5 + 3
a6 = 13 + 3
a6 = 16
a6 = 3x -2
a6 = 3*6 - 2
a6 = 18 - 2
a6 = 16 which checks.
So the general formula is
an = a_(n - 1) * k if you were multiplying or
an = a_(n - 1) + k if you were adding. The key thing is that you are working with the previous term.
