Question

Richard is 6 years older than Lisa, and in 5 years the sum of their ages will be twice as much as the sum of their ages 4 years ago. Find their present ages.

Answer 1

Answer:

Richard is 16 years old and Lisa is 10 years old

Answer 2

If we assume that Lisa is x years old, then Richard will be (x + 6)years
In 5 years time
Lisa = x +5 years
Richard = x +11 years
sum will be 2x + 16 years
4 years ago
Lisa = x-4 years
Richard = x + 2
Sum will be 2x - 2
 Therefore;
2(2x-2) = 2x +16
4x -4 = 2x +16
      2x = 20
        x = 10 
Thus, the present age of Lisa is 10 years and that of Richard is 16 years