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TiliK225 [7]
2 years ago
15

The distance between the two points P (15,x)and Q(x,-5)is 20.

Mathematics
1 answer:
Travka [436]2 years ago
6 0

Answer:

x = - 5, x = 15

Step-by-step explanation:

Assuming you require to find the values of x

Calculate the distance PQ using the distance formula and equate to 20

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-x_{1})^2    }

with (x₁, y₁ ) = P (15, x ) and (x₂, y₂ ) = Q (x, - 5 )

PQ = \sqrt{(-5-x)^2+(x-15)^2} = 20 ( square both sides )

(- 5 - x)² + (x - 15)² = 20² ← expand factors on left side using FOIL

25 + 10x + x² + x² - 30x + 225 = 400

2x² - 20x + 250 = 400 ( subtract 400 from both sides )

2x² - 20x - 150 = 0 ( divide through by 2 )

x² - 10x - 75 = 0

consider the factors of the constant term (- 75) which sum to give the coefficient of the x- term (- 10)

the factors are - 15 and + 5 , since

- 15 × 5 = - 75 and - 15 + 5 = - 10 , then

(x - 15)(x + 5) = 0

equate each factor to zero and solve for x

x + 5 = 0 ⇒ x = - 5

x - 15 = 0 ⇒ x = 15

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A company that rents small moving trucks wants to purchase 25 trucks with a combined capacity of 28,000 cubic feet. Three differ
pickupchik [31]

Answer:

We have 4 solutions:

  • No 10-foot truck, 10  14-foot trucks, and 15 24-foot trucks
  • 2 10-foot trucks, 7 14-foot trucks, and 16 24-foot trucks
  • 4 10-foot trucks, 4  14-foot trucks, and 17 24-foot trucks
  • 6 10-foot trucks, 1 14-foot trucks, and 18 24-foot trucks

Step-by-step explanation:

Let the number of 10-foot truck with a capacity of 350 cubic feet purchased=a

Let the number of 14-foot truck with a capacity of 700 cubic feet purchased=b

Let the number of 24-foot truck with a capacity of 1,400 cubic feet purchased=c

The company wants to purchase 25 trucks, therefore.

  • a+b+c=25

Furthermore, the combined capacity of the trucks is 28,000 cubic feet.

  • 350a+700b+1400c=28000

Since the number of equations is less than the number of variables, you can not use a matrix equation to solve this problem.  The solution is most easily found using an augmented matrix.  

The augmented matrix is presented below:  

\left[\begin{array}{ccc|c}1&1&1&25\\350&700&1400&28000\end{array}\right]

Using the calculator, the reduced row echelon form is:

\left[\begin{array}{ccc|c}1&0&-2&-30\\0&1&3&55\end{array}\right]

where  

a- 2c=-30 means a =2c-30

b+3c=55 means b= 55-3c

We alter the value of c as long as neither a nor b becomes negative. Suitable values for c are 15, 16, 17, and 18:

\left|\begin{array}{|c||c||c|}a=2c-30&b=55-3c&c\\0&10&15\\2&7&16\\4&4&17\\6&1&18\end{array}\right|

We can easily  verify that, for each solution, the number of trucks adds up to 25 and the fleet capacity is 28,000 cubic feet.

We therefore have 4 solutions:

  • No 10-foot truck, 10  14-foot trucks, and 15 24-foot trucks
  • 2 10-foot trucks, 7 14-foot trucks, and 16 24-foot trucks
  • 4 10-foot trucks, 4  14-foot trucks, and 17 24-foot trucks
  • 6 10-foot trucks, 1 14-foot trucks, and 18 24-foot trucks
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4 years ago
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