47.60514678
What I did was 28 squared plus b squared equals 38.25 squared and ya......
F(x)=x^3-7x-6 Since I don't have the graph and this is not a perfect cube, I will have to rely on Newton :P
x-(f(x)/(dy/dx))
x-(x^3-7x-6)/(3x^2-7)
(2x^3+6)/(3x^2-7), letting x1=0
0, -6/7, -.988, -.9999, -.99999999999, -1
(x^3-7x-6)/(x+1)
x^2 r -x^2-7x-6
-x r -6x-6
-6 r 0
(x+1)(x^2-x-6)=0
(x+1)(x-3)(x+2)=0
x= -2, -1, 3
Answer:
The answer is 350 points
Step-by-step explanation:
The Area of a circle is πr∧2
The problem states that in the attempts, you never hit the outermost ring in the 10 attempts so we need the area of the 1cm and 2cm circles
Area of the 1st circle; π X 1∧2 = π
Area of the Second circle; π X 2∧2 = 4π
We also need the area which is the difference between the area of the 1cm and 2cm circle
4π - π = π
Points 50 = π/4π = 1/4
points 30 = 3π/4π = 3/4
For one attempt,
E(x) = 50 x 1/4 + 30 x 3/4
= 12.25 + 22.5
= 34.75
This is approximately 35
Therefor, 10 individual attempts will be 10 x 35 = 350
Answer:
Step-by-step explanation:
The recursive form is a(n + 1) = a(n) + 2, with a(1) = 8.
The next term is a(6) = a(5) + 2, which heere is a(6) = 16 + 2 = 18
Answer: this my pp: 8===========================>
Step-by-step explanation:
