To find the 'maximum height' we will need to take the derivative of h(t) = –16t² + 32t + 6 then set it equal to zero, then solve for t. this t will be the time at which the ball reaches it's maximum height.
Answer:
5
Step-by-step explanation:
so 1/5 of 10 is 5 and 1/5 5 would be 1
area is LxW
so 5x1=5
C I believe hope this is correct :)