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cestrela7 [59]
3 years ago
6

The volume of a sphere is cubic inches. What is the circumference of the great circle of the sphere?

Mathematics
1 answer:
Shtirlitz [24]3 years ago
7 0
Is there a pictures?

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For which value(s) of x will the rational expression below equal zero? Check all that apply.
geniusboy [140]

Answer:

x = 5 and -2

Step-by-step explanation:

Given the function of x to be;

f(x) = (x-5)(x+2)/x+1

The value of x that will make the function zero can be calculated for by equating the given function to zero first to have;

If f(x) = 0, then;

(x-5)(x+2)/x+1 = 0

Cross multiplying;

(x-5)(x+2) = 0

(x-5) = 0 and x+2 = 0

x = 5 and x = -2

The value of x that will make the function zero is therefore 5 and -2

4 0
3 years ago
Read 2 more answers
9x + 9 + 2x - 7(3 + x) =
SashulF [63]

Answer:

4x-12 or 4(x-3)

Step-by-step explanation:

9x+9+2x-7(3+x)

9x+2x+9-21-7x

11x-12-7x

11x-7x-12

4x-12

4 0
3 years ago
Find the area of the regular polygon. Round your answer to the nearest tenth. 344.3 in.2 172.2 in.2 84.4 in.2 50.0 in.2
My name is Ann [436]
Area = \frac{a X p}{2}
Area = apothem times perimeter over 2



7 0
3 years ago
Which of the equations below could be the equation of this parabola?
nirvana33 [79]

Answer:

 y=-4x^2  is the equation of this parabola.

Step-by-step explanation:

Let us consider the equation

y=-4x^2

\mathrm{Domain\:of\:}\:-4x^2\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

\mathrm{Range\:of\:}-4x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\le \:0\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:0]\end{bmatrix}

\mathrm{Axis\:interception\:points\:of}\:-4x^2:\quad \mathrm{X\:Intercepts}:\:\left(0,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:0\right)

As

\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=a\left(x-m\right)\left(x-n\right)

\mathrm{is\:the\:average\:of\:the\:zeros}\:x_v=\frac{m+n}{2}

y=-4x^2

\mathrm{The\:parabola\:params\:are:}

a=-4,\:m=0,\:n=0

x_v=\frac{m+n}{2}

x_v=\frac{0+0}{2}

x_v=0

\mathrm{Plug\:in}\:\:x_v=0\:\mathrm{to\:find\:the}\:y_v\:\mathrm{value}

y_v=-4\cdot \:0^2

y_v=0

Therefore, the parabola vertex is

\left(0,\:0\right)

\mathrm{If}\:a

\mathrm{If}\:a>0,\:\mathrm{then\:the\:vertex\:is\:a\:minimum\:value}

a=-4

\mathrm{Maximum}\space\left(0,\:0\right)

so,

\mathrm{Vertex\:of}\:-4x^2:\quad \mathrm{Maximum}\space\left(0,\:0\right)

Therefore,  y=-4x^2  is the equation of this parabola. The graph is also attached.

7 0
3 years ago
Help ! solve the following system of equations <br><br> -9x+2y=-13<br><br> 2x-9y=20
Stella [2.4K]

Answer: x = 1, y = -2

Step-by-step explanation:

-9x+2y=-13

x= 13/9 + 2/9y

2x-9y=20

2(13/9+2/9y)-9y=20

<em>Substitute y with -2.</em>

<em />

x= 13/9+2/9(-2)

<em>After solving you'll see that 1 is a possible solution for x.</em>

<em />

Check your answer

-9x+2y=-13

-9x1+2(-2) = -13

2x-9y=20

2x1-9(-2) = 20

-13 = -13

20 = 20

Therefore, x=1 and y=-2

5 0
3 years ago
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