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kotykmax [81]
3 years ago
14

What is greater 2yd or 6ft and the other question is 3 ft or 30in

Mathematics
2 answers:
lora16 [44]3 years ago
5 0
They are the same. Neither of them is greater than the other.
Artemon [7]3 years ago
4 0
2yd = 6ft 

3ft > 30 in 

2 yards is equal to 6 ft 

3 feet is greated than 30 inches
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Let n1equals50​, Upper X 1equals30​, n2equals50​, and Upper X 2equals10. Complete parts​ (a) and​ (b) below. a. At the 0.05 leve
Viefleur [7K]

Answer:

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

z=\frac{0.6-0.2}{\sqrt{0.4(1-0.4)(\frac{1}{50}+\frac{1}{50})}}=4.082    

p_v =2*P(Z>4.082)=4.46x10^{-5}  

So the p value is a very low value and using any significance level for example \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion 1 is significantly different from proportion 2.

Step-by-step explanation:

1) Data given and notation  

X_{1}=30 represent the number of people with a characteristic in 1

X_{2}=10 represent the number of people with a characteristic in 2

n_{1}=50 sample of 1 selected  

n_{2}=50 sample of 2 selected  

p_{1}=\frac{30}{50}=0.6 represent the proportion of people with a characteristic in 1

p_{2}=\frac{10}{50}=0.2 represent the proportion of people with a characteristic in 2

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the proportion 1 is different from proportion 2 , the system of hypothesis would be:  

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{30+10}{50+50}=0.4  

3) Calculate the statistic  

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.6-0.2}{\sqrt{0.4(1-0.4)(\frac{1}{50}+\frac{1}{50})}}=4.082    

4) Statistical decision

For this case we don't have a significance level provided \alpha, but we can calculate the p value for this test.    

Since is a two sided test the p value would be:  

p_v =2*P(Z>4.082)=4.46x10^{-5}  

So the p value is a very low value and using any significance level for example \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion 1 is significantly different from proportion 2.  

3 0
3 years ago
Someone please help correct answers only
sergeinik [125]
I think the correct answer is P=3
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8 0
3 years ago
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A).
insens350 [35]

Answer:

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Step-by-step explanation:

6 0
3 years ago
FIND THE AREA OF THE RECTANGLE!!!!!!!!
Alex Ar [27]
2-5 x 1/2 = 0.2 (Length x Width)
7 0
4 years ago
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One antifreeze solution is 20% alcohol. Another antifreeze solution is 12% alcohol. How many liters of each solution should be c
katrin [286]
Use this systems of equations to solve:

x = first antifreeze
y = second antifreeze

\left \{ {{.2x + .12y = .18(15)} \atop {x + y = 15}} \right.

Isolate y.

x + y = 15
Subtract x from both sides.
y = -x + 15

Substitute y into the other equation.

.2x + .12(-x + 15) = .18(15)
Simplify.
.2x - .12x + 1.8 = 2.7
Subtract 1.8 from both sides.
.08x = .9
Divide both sides by .08
x = 11.25

Substitute x in the equation that we isolated y in.

y = -11.25 + 15
y = 3.75

11.25 L of the first antifreeze and 3.75 L of the second.
5 0
3 years ago
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