Question

At the end of January 2003, the population of my town was 11,212. The population of my town increases by 322 every month. In what month does the population of my town first exceed 15,000?

Answer 1

In 11.76 months, the value of the population will be 15000.

We have given that,

At the end of January 2003, the population of my town was 11,212.

the population is increased by 322 every month

So at the end of the second-month population will be 11534.

suppose x represents the year and  y represent the population

The population increased by 322 every month

Therefore the value of m =322

$(x_1,y_1)=(0,11212)$

We have m=332

$(x_2,y_2)=(x_2,15000)$

We have to determine the value of the x_2

What is the slope point form of the line?

$(y_2-y_1)=m(x_2-x_1)$

$322\left(x_2-0\right)=15000-11212$

$322\left(x_2-0\right)=3788$

$\frac{322\left(x_2-0\right)}{322}=\frac{3788}{322}$

$x_2=\frac{1894}{161}$

$x_2=11.76$

Therefore in 11.76 months, the value of the population will be 15000.

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