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erastovalidia [21]

3 years ago

12

A water sprinkler covers a circular area with a diameter of 20 feet. If it is set to cover only an arc measuring 120 degrees, wh

ich is the closest to the area, in square feet, the sprinkler will cover

1 answer:

Wewaii [24]3 years ago

4 0

<u>Answer:</u>

The sprinkler will cover 104.66 square feet

<u>Explanation:</u>

A water sprinkler covers a circular area with a diameter D= 20 feet

and radius r = 10 feet

Arc measuring degrees = 120 degree

Area of the Arc = $\frac{120}{360} \times \pi \times r^2$

= $\frac{1}{3} \times \pi \times 10^2$

= $\frac{1}{3} \times 3.14 \times 10 \times 10$

= 104.66

The sprinkler will cover an arc area covering 104.66 square feet

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A jumping spider's movement is modeled by a parabola. The spider makes a single jump from the origin and reaches a maximum heigh

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A parabola is a mirror-symmetrical U-shape.

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Substitute the values of a and the vertex in $\mathbf{Focus = (h, \frac{k+1}{4a})}$

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So, we have:

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$\mathbf{y = -\frac{1}{640}(x - 80)^2 + 10}$

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A quadratic function is represented as:

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