Determine the standard form of the equation of the line that passes through (-2, 0) and (-8, 5).
1 answer:
Answer:
5x + 6y = -10
Step-by-step explanation:
(-2, 0) and (-8, 5)
m = (y₂ - y₁) / (x₂ - x₁)
m = (5 - 0) / (-8 -(-2)
m = 5 / (-8+2)
m = -5/6
y = mx + b
(-8, 5)
5 = -5/6(-8) + b
5 = 40/6 + b
b = 5 - 40/6
b = -5/3
y = mx + b
y = -5/6x - 5/3 *6
6y = -5x -5(2)
6y = -5x - 10
5x + 6y = -10
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