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3 years ago

Determine the standard form of the equation of the line that passes through (-2, 0) and (-8, 5).

Mathematics

1 answer:

Vladimir79 [104]3 years ago

8 0

Answer:

5x + 6y = -10

Step-by-step explanation:

(-2, 0) and (-8, 5)

m = (y₂ - y₁) / (x₂ - x₁)

m = (5 - 0) / (-8 -(-2)

m = 5 / (-8+2)

m = -5/6

y = mx + b

(-8, 5)

5 = -5/6(-8) + b

5 = 40/6 + b

b = 5 - 40/6

b = -5/3

y = mx + b

y = -5/6x - 5/3 *6

6y = -5x -5(2)

6y = -5x - 10

5x + 6y = -10

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mezya [45]

Answer:

Total number of puppies in the litter = 11

Step-by-step explanation:

Let the number of yellow puppies in the litter = y

And the number of black puppies in the litter = b

If there was one less black puppy, ratio of yellow to black puppies = $\frac{2}{3}$

$\frac{y}{b-1}=\frac{2}{3}$

2(b - 1) = 3y

3y - 2b = -2 -----(1)

If there was one more black puppy, ratio of yellow puppies to black puppies = $\frac{1}{2}$

$\frac{y}{b+1}=\frac{1}{2}$

2y = b + 1

2y - b = 1 -------(2)

Equation (1) - 2× equation (2)

(3y - 2b) - 2(2y - b) = -2 - 2

3y - 4y - 2b + 2b = -4

y = 4

From equation (1),

3×4 - 2b = -2

12 - 2b = -2

-2b = -14

b = 7

Total number of puppies in the litter = 7 + 4 = 11

4 0

3 years ago

Geometry question plz help

saw5 [17]

Answer:

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3 years ago

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igor_vitrenko [27]

Answer:

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Step-by-step explanation:

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In a cohort of 35 graduating students, there are three different prizes to be awarded. If no student can receive more than one p

sweet [91]

We have been given in a cohort of 35 graduating students, there are three different prizes to be awarded. We are asked that in how many different ways could the prizes be awarded, if no student can receive more than one prize.

To solve this problem we will use permutations.

$_{r}^{n}\textrm{P}={_{3}^{35}\textrm{P}}$

We know that formula for permutations is given as

$_{r}^{n}\textrm{P}=\frac{n!}{(n-r)!}$

On substituting the given values in the formula we get,

${_{3}^{35}\textrm{P}}=\frac{35!}{(35-3)!}=\frac{35!}{32!}$

$=\frac{35\cdot 34\cdot 33\cdot 32!}{32!}\\
\\
=35\cdot 34\cdot 33=39270$

Therefore, there are 39270 ways in which prizes can be awarded.

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3 years ago

The radius of a circle r in centimeters can be found by solving r to the second power = 70. What is the radius of the circle r,

slavikrds [6]

Answer:

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