Question

Determine the standard form of the equation of the line that passes through (-2, 0) and (-8, 5).

Answer 1

Answer:

5x + 6y = -10

Step-by-step explanation:

(-2, 0) and (-8, 5)

m = (y₂ - y₁) /  (x₂ - x₁)

m = (5 - 0) / (-8 -(-2)

m = 5 / (-8+2)

m = -5/6

y = mx + b

(-8, 5)

5 = -5/6(-8) + b

5 = 40/6 + b

b = 5 - 40/6

b = -5/3

y = mx + b

y = -5/6x - 5/3           *6

6y = -5x -5(2)

6y = -5x - 10

5x + 6y = -10