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Hatshy [7]
2 years ago
5

HELP ME PLEASEEEEEEEEEEEEEEEEEE

Mathematics
1 answer:
kumpel [21]2 years ago
5 0
For this case we have the following solution.
 First, let's give the variable a name:
 Let
 x = gallons of water to be added
 For the 10% solution we have:
 0.1 * 8 = 0.8
 Then, for 5% we have:
 (0.8 / x + 8) = 0.05
 Rewriting:
 (0.8 / x + 8) = (5/100)
 Answer:
 An equation can be used to find x, the humber of gallons of water he should add is:
 (0.8 / x + 8) = (5/100) (option 2).
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Suma de polinomios de 5׳+3 + 2׳-ײ+1 porfavor ayuda​
Sidana [21]

<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<33<3<3<3<3

Let's simplify step-by-step.

5x^3 + 3 + 2x^3 − x^2 + 1

= 5x^3 + 3 + 2x^3 + −x^2 + 1

Combine Like Terms:

= 5x^3 + 3 + 2x^3 + −x^2 + 1

= ( 5x^3 + 2x^3 ) + ( −x^2 ) + ( 3 + 1 )

= 7x^3 + −x^2 + 4

Answer:

= 7x^3 − x^2 + 4

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5 0
3 years ago
Round to the place value of the underlined digit 301.587
DerKrebs [107]

round too? hundreds? thousand? ones? where do we round too? i need to know so i can help you :)


4 0
3 years ago
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IrinaVladis [17]
The correct answer is -15 because the absolute value is 15 but there is a negative outside the absolute value lines making it negative :)
7 0
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Read 2 more answers
Two boats leave a dock at the same time. One boat travels south at 32 mi divided by hr32 mi/hr and the other travels east at 60
TEA [102]

Answer: the rate at which the distance between the boats is​ increasing is 68 mph

Step-by-step explanation:

The direction of movement of both boats forms a right angle triangle. The distance travelled due south and due east by both boats represents the legs of the triangle. Their distance apart after t hours represents the hypotenuse of the right angle triangle.

Let x represent the length the shorter leg(south) of the right angle triangle.

Let y represent the length the longer leg(east) of the right angle triangle.

Let z represent the hypotenuse.

Applying Pythagoras theorem

Hypotenuse² = opposite side² + adjacent side²

Therefore

z² = x² + y²

To determine the rate at which the distances are changing, we would differentiate with respect to t. It becomes

2zdz/dt = 2xdx/dt + 2ydy/dt- - - -- - -1

One travels south at 32 mi/h and the other travels east at 60 mi/h. It means that

dx/dt = 32

dy/dt = 60

Distance = speed × time

Since t = 0.5 hour, then

x = 32 × 0.5 = 16 miles

y = 60 × 0.5 = 30 miles

z² = 16² + 30² = 256 + 900

z = √1156

z = 34 miles

Substituting these values into equation 1, it becomes

2 × 34 × dz/dt = (2 × 16 × 32) + 2 × 30 × 60

68dz/dt = 1024 + 3600

68dz/dt = 4624

dz/dt = 4624/68

dz/dt = 68 mph

6 0
3 years ago
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