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Tpy6a [65]
3 years ago
15

Choose three intervals on the real number line that contain both rational and irrational numbers. Do you think that any given in

te number line contains both rational and irrational numbers? Explain.
Mathematics
1 answer:
Helen [10]3 years ago
3 0

Any real number line ranges from negative infinity to positive infinity. A real number number line consists of all the rational and irrational numbers. Let us take three intervals which contain both the rational and irrational numbers.

First interval:  [3,4]

Since every integer is a rational number, 3 and 4 are both rational. In this interval there occurs the value of π (3.14159..) which is an irrational number.

Second interval :  [0,2]

0 and 2 are integers and hence are rational. In this interval, occurs √2 (1.41421...) is an irrational number.

Third interval : [2,3]

In this interval, Eulers number 'e' lie whose value is (2.718281.. )

Hence we can conclude that, there occurs an irrational number between any two rational number.

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R(-1,-3), S(4,4), T(8,-1)<br><br><br> PLZ HELP ME
Bingel [31]

9514 1404 393

Answer:

  see attachments

Step-by-step explanation:

The side lengths are found using the distance formula.

  d = √((x2-x1)^2 +(y2-y1)^2)

For example, the length of RS in the first triangle is ...

  d = √((4-(-1))^2 +(4-(-3))^2) = √(25 +49) = √74 ≈ 8.602

This same computation is used for all of the sides of the triangles. When the same tedious computation is repeated over and over, I like to use a spreadsheet to do it. In the attached spreadsheet the two points used are the one on the same line as the distance, and the one on the line below. Side lengths are shown in the attachment to 3 decimal places.

__

In order to classify the triangle as acute, right, or obtuse, we can compare the side lengths to those of a right triangle. For the purposes of computation in a spreadsheet, it is convenient to compute the middle length side of a right triangle that has the same longest and shortest sides as the triangle we have.

If the computed side is longer than the actual middle side, then the triangle we have is obtuse. If it is shorter, the triangle we have is acute. If it is exactly the same, then the triangle we have is a right triangle.

In every case here, the computed middle side is shorter than the actual middle-length side, so all of the triangles are acute triangles. (The one of problem 39 is isosceles, since two sides are the same length. The others are scalene.)

__

The triangles are graphed in the second attachment.

  problem 38: RST

  problem 39: ABC

  problem 40: DEF

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