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Tpy6a [65]
3 years ago
15

Choose three intervals on the real number line that contain both rational and irrational numbers. Do you think that any given in

te number line contains both rational and irrational numbers? Explain.
Mathematics
1 answer:
Helen [10]3 years ago
3 0

Any real number line ranges from negative infinity to positive infinity. A real number number line consists of all the rational and irrational numbers. Let us take three intervals which contain both the rational and irrational numbers.

First interval:  [3,4]

Since every integer is a rational number, 3 and 4 are both rational. In this interval there occurs the value of π (3.14159..) which is an irrational number.

Second interval :  [0,2]

0 and 2 are integers and hence are rational. In this interval, occurs √2 (1.41421...) is an irrational number.

Third interval : [2,3]

In this interval, Eulers number 'e' lie whose value is (2.718281.. )

Hence we can conclude that, there occurs an irrational number between any two rational number.

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B is the midpoint of AC and E' is the midpoint of BD. If A(-9,-4), C(-1, 6), and E(-4,-3), find the coordinates of D.
Ipatiy [6.2K]
The coordinates for D are (-4, -7)

First we must locate point B as it is vital to finding the midpoint of BD. To do this, we take the average of the endpoints AC since B is its midpoint. 

x values = -9 + 1 = -8
Then divide by 2 for the average -8/2 = -4

y values = -4 + 6 = 2
Then divide by 2 for the average 2/2 = 1

Therefore B must be (-4, 1)

Now we know the values of E must be the average of B and D. So we can write equations for each coordinate since we know they are averages. 

x - values = (Bx + Dx)/2 = Ex
(-4 + Dx)/2 = -4 ---> multiply both sides by 2
-4 + Dx = -8 ---> add -4 to both sides
Dx = -4

y - values = (By + Dy)/2 = Ey
(1 + Dy)/2 = -3 ---> multiply both sides by 2
1 + Dy = -6 ---> subtract 1 from both side
Dy = -7

So the coordinates for D must be (-4, -7)
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Will give 5 star, thanks, and brainliest for correct answers
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1) X=159
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