<h2>
Hello!</h2>
The answer is:
In 2036 there will be a population of 32309 rabbits.
<h2>
Why?</h2>
We can calculate the exponential decay using the following function:

Where,
Start Amount, is the starting value or amount.
Percent, is the decay rate.
t, is the time elapsed.
We are given:

Now, substituting it into the equation, we have:






Hence, we have that in 2036 the population of rabbis will be 32309 rabbits.
Have a nice day!
Multipy 3 by 6 multiply 1 by 4 and 7 by 4 then add the numbers

Step-by-step explanation:
The given equation is 
Let
be the coefficient of 
Let
be the coefficient of 
Let
be the constant.
Then the roots α,β for the equation
are 
So,α=
β=
.
So the roots are 
The function is y=2x
this means that the solutions will have the form (x, y)=(x,2x).
For example: (0,0),(1,2),(2,4),(3,6) are solutions.
The first answer choice satisfies the above conditions.
The second answer choice contains (2,2), and (2,6), both of which do not satisfy the (x,2x) condition, so it's not correct.
The third answer choice contains (4,2), which again does not satisfy (x,2x), so not the right answer.