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lianna [129]
3 years ago
7

3x + 4y = 17 -6x = 10y - 39 How many solutions

Mathematics
1 answer:
Hoochie [10]3 years ago
8 0

Answer:

(7/3, 5/2) one answer

Step-by-step explanation:

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Wich is bigger<br><br> 1.320. 1.302<br><br> &lt;<br> &gt; <br> =
elena-14-01-66 [18.8K]
1.320 >1.302 or 1.302<1.320
4 0
3 years ago
What is the product of 8.2 x 10^2 and 3.4 x 10^5
Anuta_ua [19.1K]

Answer:

278,800,000 (Real Number) or 2.788 *10^8 (Scientific Notation)

Concepts:

  • - Order of Operations

Parenthesis: ( )

Exponents: x²

Multiplication: ×

Division: ÷

Addition: +

Subtraction: -

Step-by-Step Solution:

8.2*10^2*3.4*10^5

Simplify exponents and square roots

8.2*10^2*3.4*10^5

8.2*10^2*3.4*100000

8.2*100*3.4*100000

820*3.4*100000

2788*100000

278800000

<h2>Answer:</h2>

278,800,000

Why learn this:

  • Order of operations is a basic rule of algebra. It tells us what to solve first when we have an equation with multiple functions, which is something that you will likely encounter throughout your math studies. The order is: Parentheses, Exponents, Multiplication and Division, then finally Addition and Subtraction. Remember that when you're solving within the parentheses, the Order of Operations applies!

Terms and topics

  • Order of operations

8 0
3 years ago
150 divided by 11 fraction
Andrei [34K]

Answer:

as a mixed number: 13 7/11  as a percentage 1363.64%

Step-by-step explanation:

6 0
3 years ago
Solve for x in the equation x^2-4x-9=29? x=2+/- squareroot 42 x=2+/-squareroot 33 x=2+/-squareroot 34 x=4+/-squareroot 42
jeka57 [31]
For this case what we must do is to use the formula of the resolvent in the following way:
 x = (- b +/- root (b ^ 2 - 4 * a * c)) / (2 * a)
 Where,
 a = 1
 b = -4
 c = -38
 Substituting the values:
 x = (- (- 4) +/- root ((- 4) ^ 2 - 4 * 1 * (- 38))) / (2 * 1)
 x = (4 +/- root (168)) / 2
 x = (2 +/- root (42))
 Answer:
 x = 2 +/- squareroot 42
3 0
3 years ago
It's a simple graphing problem I guess
Alex777 [14]
Answer: unidentifiable Explanation: y intercept is 0
4 0
3 years ago
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