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Lesechka [4]
3 years ago
5

A scale model of a bicycle has a scale of 1 : 10. The real bicycle has a length of 1.6 m. What is the length of the model in cm?

Mathematics
2 answers:
garri49 [273]3 years ago
7 0

Answer:

16 cm

Step-by-step explanation:

1.6 m = 160 cm

Model length = 160 / 10 = 16 cm

klio [65]3 years ago
3 0

Answer:

160 cm

Step-by-step explanation:

1 : 10

1.6 : x

Cross multiply.

1 × x = 10 × 1.6

x = 160

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Shtirlitz [24]

Divide 15 by 20 and then take that and multiply it by 16 and you'll get 12

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8 0
3 years ago
Please help me thank you​
Ket [755]

Answer: D. 2x² + 3/2.x - 5

Step-by-step explanation:

7 0
3 years ago
Which of the following slopes show that the set of points C(1, 1), D(3, -4), E(5, 8) are not collinear?
MArishka [77]
C is the answer you want

8 0
3 years ago
Read 2 more answers
Find f (20) for f(n) = -2n +6
kiruha [24]

Answer:

f(n) = -34

Step-by-step explanation:

n = 20

f(n) = -2(20) + 6

f(n)= -40 +6

f(n) = -34

3 0
3 years ago
The lengths of brook trout caught in a certain Colorado stream are normally distributed with a mean of 14 inches and a standard
mezya [45]

Answer:

0.6563 or 65.63% of brook trout caught will be between 12 and 18 inches

Step-by-step explanation:

Mean trout length (μ) = 14 inches

Standard deviation (σ) = 3 inches

The z-score for any given trout length 'X' is defined as:  

z=\frac{X-\mu}{\sigma}  e interval

For a length of X =12 inches:

z=\frac{12-14}{3}\\z=-0.6667

According to a z-score table, a score of -0.6667 is equivalent to the 25.25th percentile of the distribution.

For a length of X =18 inches:

z=\frac{18-14}{3}\\z=1.333

According to a z-score table, a score of 1.333 is equivalent to the 90.88th percentile of the distribution.

The proportion of trout caught between 12 and 18 inches, assuming a normal distribution, is the interval between the equivalent percentile of each length:

P(12\leq X\leq 18) = 90.88\% - 25.25\%\\P(12\leq X\leq 18) = 65.63\%

8 0
3 years ago
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