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CaHeK987 [17]
3 years ago
6

What does 7 + 2x = 9

Mathematics
2 answers:
miss Akunina [59]3 years ago
6 0

Answer:

1

Step-by-step explanation:

7 + 2x = 9

Carry over the 7 to the 9.

2x = 9-7

2x= 2

x = 2÷2

x = 1

Ira Lisetskai [31]3 years ago
6 0

Answer: x = 1

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

2x+7=9

Step 2: Subtract 7 from both sides.

2x+7−7=9−7

2x=2

Step 3: Divide both sides by 2.

2x/2 = 2/2 = 1

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Find the mean, variance, and standard deviation. If necessary, round your answer to the nearest hundredth.
lora16 [44]

Answer:

Mean = 24

Variance = 107.78

Standard deviation = 10.38

Hope this helps! :)

4 0
3 years ago
Rational or irrational?
Lisa [10]
Since its a square root then it would be irrational.

Hope this helps you! :)
8 0
3 years ago
If there are:
ruslelena [56]

Answer:

0.06

Step-by-step explanation:

Total number of marbles:

6 + 10 + 5 + 1 = 22 marbles

Probability of picking 1 red marble:

red marbles / total marbles

6/22

Probability of picking a green marble:

green marbles / total marbles

5/22

Now, multiply the probabilities:

6/22 • 5/22 = 15/242 = 0.06

5 0
3 years ago
Given: △ABC, AB=5 square root 2 <br><br>m∠A=45°, m∠C=30°<br><br>Find: BC and AC
hichkok12 [17]

Answer:

Part a) BC=10\ units

Part b) AC=13.66\ units

Step-by-step explanation:

step 1

Find the length side BC

Applying the law of sines

we know that

\frac{AB}{sin(C)}=\frac{BC}{sin(A)}

we have

AB=5\sqrt{2}\ units

A=45^o

C=30^o

substitute

\frac{5\sqrt{2}}{sin(30^o)}=\frac{BC}{sin(45^o)}

solve for BC

BC=\frac{5\sqrt{2}}{sin(30^o)}(sin(45^o))

BC=10\ units

step 2

Find the measure of angle B

we know that

The sum of the interior angles in a triangle must be equal to 180 degrees

so

m\angle A+m\angle B+m\angle C=180^o

substitute the given values

45^o+m\angle B+30^o=180^o

75^o+m\angle B=180^o

m\angle B=180^o-75^o

m\angle B=105^o

step 3

Find the length side AC

Applying the law of sines

we know that

\frac{AB}{sin(C)}=\frac{AC}{sin(B)}

we have

AB=5\sqrt{2}\ units

A=45^o

B=105^o

substitute

\frac{5\sqrt{2}}{sin(30^o)}=\frac{AC}{sin(105^o)}

solve for AC

AC=\frac{5\sqrt{2}}{sin(30^o)}(sin(105^o))

AC=13.66\ units

4 0
3 years ago
HELP PLEASE!!<br> Which of the following equations is true to find the length BC?
jarptica [38.1K]

Answer:

BC/sin 23 = 10/sin 47

Step-by-step explanation:

Here, we want to select the true equation to find the length BC

From the question, we have the angle facing side BC; also, we have the angle and the side facing it for another side

In this situation, the best way to solve for BC is by the use of the sine rule

The sine rule states that the ratio of the length of a side and the sine of the angle facing the side is constant for a given triangle

Thus, we have it that;

BC/sin 23 = 10/sin 47

8 0
2 years ago
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