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Serga [27]
3 years ago
14

I really need help! What is 1/5x+1/2=2(4/5x+1)

Mathematics
1 answer:
Mama L [17]3 years ago
8 0
I think this is the answer !

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Someone help me please
laila [671]

Answer:

37°

Step-by-step explanation:

You can see it is a right angle. Do 90-AOB angle=BOC angle.

4 0
2 years ago
Which expression is equivalent to (3b 2r) (4b r)? 7b 2r 7b 3r 12b 2r 12b 3r.
Maslowich

To add the variables, add the coefficients with same variable. The expression which is equivalent to given expression is 7b+3r. The option 2 is the correct option.

<h3>What is equivalent expression?</h3>

Equivalent expression are the expression whose result is equal to the original expression, but the way of representation is different.

Given information-

The expression given in the problem is,

(3b+2r)+(4b+r)

Let the resultant expression of the above expression is x. thus,

x=(3b+2r)+(4b+r)

To add the algebraic terms open the brackets first,

x=3b+2r+4b+r

Separate the same variable terms,

x=3b+4b+2r+r

To add the variables, add the coefficients with same variable. Thus,

x=7b+3r

Hence, the expression which is equivalent to given expression is 7b+3r. The option 2 is the correct option.

Learn more about the equivalent expression here;

brainly.com/question/2972832

4 0
2 years ago
Write an expression that is equal to 10 using only four 2s and any number of math symbols​
diamong [38]

(4 \times 2) + 2

8 0
3 years ago
Read 2 more answers
Show that the equation 2x + 3 cos x + e ^ x = 0 has a root on the interval [- 1, 0]
ExtremeBDS [4]

If <em>x</em> = -1, you have

2(-1) + 3 cos(-1) + <em>e</em> ⁻¹ ≈ -0.0112136 < 0

and if <em>x</em> = 0, you have

2(0) + 3 cos(0) + <em>e</em> ⁰ = 4 > 0

The function <em>f(x)</em> = 2<em>x</em> + 3 cos(<em>x</em>) + <em>eˣ</em> is continuous over the real numbers, so the intermediate value theorem applies, and it says that there is some -1 < <em>c</em> < 0 such that <em>f(c)</em> = 0.

5 0
3 years ago
A sphere has a volume of V=900 in cubed. What is the surface area?
ycow [4]
First, we must solve for the radius of the sphere:
V=\frac{4}{3}\pir^{3}
r=(3\frac{V}{4 \pi })^{ \frac{1}{3} }
r=(3*\frac{900}{4 \pi })^{ \frac{1}{3} }
r≈5.99

Second, we must solve for surface area:
A=4\pir^{2}
A=4*\pi*5.99^{2}
A≈450.88 in^{2}
4 0
3 years ago
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