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lisabon 2012 [21]
2 years ago
5

8.

Mathematics
1 answer:
shusha [124]2 years ago
5 0

Answer:

Axis of symmetry: x = –1; Vertex: (–1, 0); f(x) = –2x2 – 2x – 1

Step-by-step explanation:

What are the vertex and axis of symmetry of the equation?

The axis of symmetry always passes through the vertex of the parabola . The x -coordinate of the vertex is the equation of the axis of symmetry of the parabola. For a quadratic function in standard form, y=ax2+bx+c , the axis of symmetry is a vertical line x=−b2a .

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pshichka [43]
Answer: 56 times

Pls mark brainleist i really need it
7 0
2 years ago
Write the power set of the set A={a,b,c}​
Burka [1]

Answer:

P(A) = {{a},{b},{c},{a,b},{a,c},{b,c},{a,b,c},∅}

Step-by-step explanation:

➨ Power Set is the set of all subsets.

First, find the subset of A.

{a},{b},{c},{a,b},{a,c},{b,c},{a,b,c},∅

If you aren't sure that you already have written all subsets or not, use the following formula.

2^n ➩ where n is the number of element/members.

Our number of members are 3, use the following formula.

2^3=8

Thus, our subsets should be 8.

As we've already gathered all subsets, write the braces all whole subsets.

P(A) = {{a},{b},{c},{a,b},{a,c},{b,c},{a,b,c},∅}

8 0
3 years ago
An electric current, I, in amps, is given by I=cos(wt)+√8sin(wt), where w≠0 is a constant. What are the maximum and minimum valu
exis [7]
Take the derivative with respect to t
- w \sin(wt) + \sqrt{8} w cos(wt)
the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero
0 = -w \sin(wt) + \sqrt{8} w cos(wt)
divide by w
0 =- \sin(wt) + \sqrt{8} cos(wt)
we add sin(wt) to both sides

\sin(wt)= \sqrt{8} cos(wt)
divide both sides by cos(wt)
\frac{sin(wt)}{cos(wt)}= \sqrt{8}   \\  \\ arctan(tan(wt))=arctan( \sqrt{8} ) \\  \\ wt=arctan(2 \sqrt{2)} OR\\ wt=arctan( { \frac{1}{ \sqrt{2} } )
(wt)=2(n*pi-arctan(2^0.5))
(wt)=2(n*pi+arctan(2^-0.5))
where n is an integer
the absolute max and min will be

I=cos(2n \pi -2arctan( \sqrt{2} ))
since 2npi is just the period of cos
cos(2arctan( \sqrt{2} ))= \frac{-1}{3} 

substituting our second soultion we get
I=cos(2n \pi +2arctan( \frac{1}{ \sqrt{2} } ))
since 2npi is the period
I=cos(2arctan( \frac{1}{ \sqrt{2}} ))= \frac{1}{3}
so the maximum value =\frac{1}{3}
minimum value =- \frac{1}{3}


4 0
3 years ago
Find the values of X and Y in an isosceles triangle where one angle is 47°
vladimir1956 [14]

Answer:

X and Y = 66.5°.

Step-by-step explanation:

I am assuming that X and Y are the base angles, which are equal in an isosceles triangle.

X = Y = (180 - 47) / 2

=  66.5°.

6 0
2 years ago
Please find the domain and range!
SpyIntel [72]

Answer:

Domain: {-2, -3, 6, 8, 10}

Range: {-5, 1, 7, 9}

Step-by-step explanation:

Given:

{(6, -5), (-2, 9), (-3, 1), (10, 7), (8, 9)}

✔️Domain:

This includes all the set of the x-values that are in the relation. This includes, 6, -2, -3, 10, and 8.

Thus, the domain can be represented as:

{-2, -3, 6, 8, 10}

✔️Range:

This includes all corresponding y-values in the relation. They are, -5, 1, 7, and 9.

Range can be represented as:

{-5, 1, 7, 9}

3 0
3 years ago
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