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2 years ago

8.

Mathematics

1 answer:

shusha [124]2 years ago

5 0

Answer:

Axis of symmetry: x = –1; Vertex: (–1, 0); f(x) = –2x2 – 2x – 1

Step-by-step explanation:

What are the vertex and axis of symmetry of the equation?

The axis of symmetry always passes through the vertex of the parabola . The x -coordinate of the vertex is the equation of the axis of symmetry of the parabola. For a quadratic function in standard form, y=ax2+bx+c , the axis of symmetry is a vertical line x=−b2a .

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A dice is tossed 3 times. Let X be the sum of the 3 numbers obtained

UNO [17]

X + 3 (3) will be the answer

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3 years ago

A marketing firm would like to test-market the name of a new energy drink targeted at 18- to 29-year-olds via social media. A st

Anon25 [30]

Answer:

(a) The probability that a randomly selected U.S. adult uses social media is 0.35.

(b) The probability that a randomly selected U.S. adult is aged 18–29 is 0.22.

Step-by-step explanation:

Denote the events as follows:

X = an US adult who does not uses social media.

Y = an US adult between the ages 18 and 29.

Z = an US adult between the ages 30 and above.

The information provided is:

P (X) = 0.35

P (Z) = 0.78

P (Y ∪ X') = 0.672

(a)

Compute the probability that a randomly selected U.S. adult uses social media as follows:

P (US adult uses social media (X')) = 1 - P (US adult so not use social media)

$=1-P(X)\\=1-0.35\\=0.65$

Thus, the probability that a randomly selected U.S. adult uses social media is 0.35.

(b)

Compute the probability that a randomly selected U.S. adult is aged 18–29 as follows:

P (Adults between 18 - 29 (Y)) = 1 - P (Adults 30 or above)

$=1-P(Z)\\=1-0.78\\=0.22$

Thus, the probability that a randomly selected U.S. adult is aged 18–29 is 0.22.

(c)

Compute the probability that a randomly selected U.S. adult is 18–29 and a user of social media as follows:

P (Y ∩ X') = P (Y) + P (X') - P (Y ∪ X')

$=0.22+0.65-0.672\\=0.198$

Thus, the probability that a randomly selected U.S. adult is 18–29 and a user of social media is 0.198.

6 0

3 years ago

I really need help with this

aniked [119]

Answer:

5√202

Step-by-step explanation:

By Pythagoras theorem,

x^2 = 45^2 + 55^2

= 2025 + 3025

x^2 = 5050

x = 5√202

5 0

3 years ago

Stardust the unicorn, covered a distance of 50 miles on his first trip to the forest. On a later trip he travelled 300 miles whi

timama [110]

For this case, the first thing we must take into account is the following definition:
d = v * t
Where,
d: distance
v: speed
t: time
Substituting values we have:
Trip 1:
50 = v * t1
We cleared t1:
t2 = (50) * (1 / v)
Trip 2:
300 = (3 * v) * t2
We cleared t2:
t2 = (300/3) * (1 / v)
t2 = (100) * (1 / v)
Rewriting:
t2 = 2 (50) * (1 / v)
t2 = 2 * t1
Answer:
His new time compared with the old time was:
Twice the old time.
t2 = 2 * t1.

4 0

3 years ago

Suppose a subset of eight different days of the year is selected at random. What is the probability that each day is from a diff

goldfiish [28.3K]

Answer:

P = 0.05

Step-by-step explanation:

12 months * 30 days each = 360 days

From 306 days, we have to select 8 days = 360C8 ways(Total ways)

We want each days from different month. First, we have to select 8 month from 12 month = 12C8 ways

---By selecting 8 month, we will select a days from each month. That can be done in = 30C1 * 30C1 * .................30C1 (8 ways) [From a month with 30 days, we can select a day in 30C1 ways = 30 ways]

Therefore P = Number of ways of selecting each days from different month / Total number of ways

P = 12C8 * 30^8 / 360C8

P = 495 * 656100000000 / 6469697679132645

P = 0.0501985588982791

P = 0.05

Hence the probability that each day is from a different month is 0.05

6 0

2 years ago