Answer:
The approximatel velocity of the proton after the time interval t = 3.3 × 10^-14s is Vp = (3883, 1300, 0)m/s. This result was gotten on the assumption that the force of the HCl molecule on the proton was constant during the given time interval. This allows us to apply Newton's second law of motion easily which is stated mathematically as
F = ma = m(v - u)/t
Using that formula and rearranging gives the formula for v which the required variable.
Explanation:
Full solution can be found in the attachment below.
Thank you for reading.
Answer:
Explanation:
We know that, the force responsible for circulating in circular path is the centripetal force given by the force on charged particle due to magnetic field.
Here the charge is antiproton is
p = -1.6 * 10⁻¹⁹C
the speed of proton is given by 1.5 * 10 ⁴ m/s
the magnetic field is B = 4.5 * 10⁻³T
we have force due to magnetic field is equal to centripetal force
Bqv = mv² / r
Bq = mv / r
The diameter d of the vacuum chamber have to allow these antiprotons to circulate without touching the walls is
d = 2r
d = 2 * 3.479
d = 6.958
d ≅ 7cm
Answer:
ΔV =12.38 V
Explanation:
Given that
V= 12.6 V
r= 0.057 Ω
R= 3.3Ω
The equivalent resistance
R'=r+R
R'=3.3 + 0.057
R'=3.357 Ω
We know that
V= I R'
I =Current
12.6= I x 3.357
I=3.375 A
The voltage difference across the headlight bulbs
ΔV = I R
ΔV = 3.375 x 3.3
ΔV =12.38 V
Answer:
Option D
The frequency
Explanation:
The speed of wave is depedant only on the wavelength and frequency of waves since it is given by s=fw where s is the speed, f is frequency and w is the wavelength. Since the options given has only one factor, that is frequency, hence option D is correct. In case we had wavelength could be among the options, both would be correct.