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3 years ago

How does the law of conservation of mass apply to this reaction: Mg + HCI + H2 MgClz?

Physics

1 answer:

Brums [2.3K]3 years ago

4 0

It’s the first answer - ie the equation needs to be balanced.

You can’t just look at the individual elements. To balance the equation, Magnesium will be part of the balancing and hence you will be adding Magnesium to both sides of the equation etc

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A displacement is related to time as x = A sin(2?ft), where A and f are constants. Find the dimensions of A. [Hint: A trigonomet

Luba_88 [7]

Answer:

The right option is C. i.e L

Explanation:

Dimension of a quantity is the collection of the indexes of each of the fundamental quantities contained in it.

Therefore, to get the dimension of A in the equation

X=Asin(2(pi)ft)

Making A the subject of the formula

A = X / (sin(2(pi)ft)

Since sin(2(pi)ft which is a trigonometric function does not have a dimension

A = L

The dimension of A is L

5 0

3 years ago

Light described as what two things?

seraphim [82]

Answer:modeled as an electromagnetic wave. In this model, a changing electric field creates a changing magnetic field.

Explanation:

7 0

3 years ago

HURRY!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Nata [24]

When the child is moving fastest

6 0

3 years ago

Read 2 more answers

1) What is the power in horsepower of a 100 watt light bulb? What is the power in kilowatts of a 200 horsepower engine?

Yuki888 [10]

1). Use the definition 1 Horsepower = 746 watts

100 watts = (100/746) HP = 0.134 Horsepower

2). Use the definition Power = (work done) / (time to do the work)

and the definition Work = (force) x (distance moved)

(3,000 N x 5 m) / second

= (3,000 x 5 N-m) / second

= (15,000 joules) / second

= 15,000 watts

3). Use the definition Power = (work done) / (time to do the work) , and the definition Work = (force) x (distance moved) , and the 'customary' definition of 1 Horsepower = 550 foot-pounds per second.

Let the answer ... the number of gallons ... be called ' G ' until we know what it actually is.

Weight of water lifted in 1 minute = (G gallons) x (8.34 pounds/gallon)

The distance it's lifted = 30 feet

Work done in 1 minute = (force x distance) = (8.34G x 30) foot-pounds

In just a moment, we're going to need this in seconds:

Power = (8.34G x 30 foot-pounds/minute) x (1 minute / 60 seconds)

Power = (8.34G x 30/60) (foot-pound-minute/minute-sec)

Power = 4.17G foot-pound/sec

The power = 1/2 Horsepower = 225 foot-pounds / sec

So finally, 225 = 4.17G

Divide each side by 4.17, and we have

G = (225/4.17) gallons

G = 53.96 gallons

I really should check this over, but I've had it up to here with gallons, feet, horsepower, and pounds, so I'm not gonna do it. Read my lips. It is what it is. I stand or fall by my answer. What could go wrong ? !

3 0

3 years ago

A piston–cylinder assembly contains 5.0 kg of air, initially at 2.0 bar, 30 oF. The air undergoes a process to a state where the

vladimir2022 [97]

Answer:

The work and heat transfer for this process is = 270.588 kJ

Explanation:

Take properties of air from an ideal gas table. R = 0.287 kJ/kg-k

The Pressure-Volume relation is PV = C

T = C for isothermal process

Calculating for the work done in isothermal process

W = P₁V₁ $ln[\frac{P_{1} }{P_{2} }]$

= mRT₁ $ln[\frac{P_{1} }{P_{2} }]$ [∵pV = mRT]

= (5) (0.287) (272.039) $ln[\frac{2.0}{1.0}]$

= 270.588 kJ

Since the process is isothermal, Internal energy change is zero

ΔU = $mc_{v}(T_{2} - T_{1} ) = 0$

From 1st law of thermodynamics

Q = ΔU + W

= 0 + 270.588

= 270.588 kJ

4 0

3 years ago