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Artemon [7]
4 years ago
5

F (x) when x = 1 for the function f (x) = −x2 − 3.

Mathematics
1 answer:
zepelin [54]4 years ago
4 0
The answer is - x 2-3
put x=1
(-1)2-3
-2 -3
=-5
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Plastic parts produced by an injection-molding operation are checked for conformance to specifications. Each tool contains 15 ca
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Answer:

a) 0.4352

b) 0.5165

c) 0.0813

Step-by-step explanation:

In this problem we have 3 defective parts scattered among 15 parts.

We are going to select 3 out of 15 without replacement, so the situation can be modeled with the Hypergeometric distribution.

If X is the random variable that measures the number of defective parts in a sample of 3, the probability of selecting exactly k defective parts out of 15 would be given by

P(X=k)=\displaystyle\frac{\binom{3}{k}\binom{15-3}{3-k}}{\binom{15}{3}}

a) what is the probability that the inspector finds exactly one nonconforming part?

Replacing k with 1 in our previous formula, we get

P(X=1)=\displaystyle\frac{\binom{3}{1}\binom{15-3}{3-1}}{\binom{15}{3}}=\displaystyle\frac{3*66}{455}=0.4352

b) what is the probability that the inspector finds at least one nonconforming part?

This would be P(X=1)+P(X=2)+P(X=3) = 1 - P(X=0).  

P(X=0)=\displaystyle\frac{\binom{3}{0}\binom{15-3}{3-0}}{\binom{15}{3}}=\displaystyle\frac{1*220}{455}=0.4835

so 1 - P(X=0) = 1 - 0.4835 = 0.5165

c) what is the probability that the inspector finds at least two nonconforming part?

 

P(X=2) + P(X=3) = 1 - (P(X=0) + P(X=1)) = 1 - (0.4835 + 0.4352) =

= 1 - 0.9187 = 0.0813

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Please see attached graph

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g(x = -3) = |(-3)+3| = |0| = 0

f(x = 0) = |0| = 0

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