Question

Find the difference 60 degrees 50 minutes 40 seconds subtract 30 degrees 40 minutes 50 seconds

Answer 1

Answer:

Step-by-step explanation:

According to the question,

60 degrees 50 minutes 40 seconds subtract 30 degree 40 minutes 50 seconds.

⇒$60^{{\circ}}50^{'}40^{''}-30^{{\circ}}40^{'}50^{''}$

⇒$60+(50{\times}\frac{1}{60})+(40{\times}\frac{1}{60}{\times}\frac{1}{60})-(30+(40{\times}\frac{1}{60})+(50{\times}\frac{1}{60}{\times}\frac{1}{60}))$

⇒$60+\frac{5}{6}+\frac{1}{90}-(30+\frac{2}{3}+\frac{1}{72})$

⇒$60+\frac{5}{6}+\frac{1}{90}-30-\frac{2}{3}-\frac{1}{72}$

⇒$60+0.84+0.02-30-0.67-0.02$

⇒$60.86-30-0.67-0.02$

⇒$30.17..$ degrees.