Find the difference 60 degrees 50 minutes 40 seconds subtract 30 degrees 40 minutes 50 seconds

Mathematics

1 answer:

zhannawk [14.2K]3 years ago

8 0

Answer:

Step-by-step explanation:

According to the question,

60 degrees 50 minutes 40 seconds subtract 30 degree 40 minutes 50 seconds.

⇒ $60^{{\circ}}50^{'}40^{''}-30^{{\circ}}40^{'}50^{''}$

⇒ $60+(50{\times}\frac{1}{60})+(40{\times}\frac{1}{60}{\times}\frac{1}{60})-(30+(40{\times}\frac{1}{60})+(50{\times}\frac{1}{60}{\times}\frac{1}{60}))$

⇒ $60+\frac{5}{6}+\frac{1}{90}-(30+\frac{2}{3}+\frac{1}{72})$

⇒ $60+\frac{5}{6}+\frac{1}{90}-30-\frac{2}{3}-\frac{1}{72}$

⇒ $60+0.84+0.02-30-0.67-0.02$

⇒ $60.86-30-0.67-0.02$

⇒ $30.17..$ degrees.

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