All categories

3 years ago

Give an example of a rational function that has a horizontal asymptote at y = 0 and a vertical asymptote at

2 answers:

8 0

F(x)=x^2/(x-2)(x-1), the degree of the numerator and the degree of the denominator equal and the quotient of their coefficient equal to 1(horizontal asymptote means that the lines approach a certain number when the input approaches positive or negative infinity)
and when plugging in 2 or 1 as input, the output is undefined.

dem82 [27]3 years ago

3 0

Answer:

x/(x-2)(x-1)

Step-by-step explanation: if m<n then horizontal asymptote is y=0

in the function x/(x-2)(x-1) m is bigger then n so y=0

after calculating the vertical asymptote we got x=2 and x=1

hope it helps

You might be interested in

What happens to the graph of a line when the slope is negative? Check all that apply. may choose more then 1.

Ne4ueva [31]

The Answer is A. As the absolute value of the negative slope gets bigger, the graph of the line gets steeper and C.The line goes down from left to right.

7 0

3 years ago

What is the volume of the rectangular prism

sdas [7]

All you need to do is multiply all the given measurements together.

16 x 9 x 9 = 1,296³

6 0

3 years ago

Read 2 more answers

How do I verify this identity? I know you should write sin2a as sin(a+a).

Kisachek [45]

SOLUTION

Given the question in the image, the following are the solution steps to verify the identity

STEP 1: Write the given identity

$\sin 2\alpha=2\sin \alpha\cos \alpha$

STEP 2: Verify the identity

$\begin{gathered} \sin 2\alpha=2\sin \alpha\cos \alpha \\ \text{Consider the left hand side of the above trigonometry identity.} \\ \text{That is, }\sin 2\alpha\text{.} \\ \text{ Rewrite }\sin 2\alpha\text{ as }\sin (\alpha+a) \\ \text{ It is known that }\sin (a+b)=\sin (a)\cos b+\cos (a)\sin (b) \\ U\sin g\text{ this statement above, we have;} \\ \sin (\alpha+a)=\sin a\cos \alpha+\cos a\sin \alpha \\ \text{It is known that }xy+yx=xy+xy=2\times xy=2xy \\ U\sin g\text{ this statement above, we have;} \\ \sin a\cos \alpha+\cos a\sin \alpha=\sin a\cos \alpha+\sin \alpha\cos \alpha=2\times\sin \alpha\cos \alpha=2\sin \alpha\cos \alpha \\ \text{Hence, }\sin 2\alpha=2\sin \alpha\cos \alpha \end{gathered}$

The verification of the identity is as seen above.

7 0

1 year ago

4.06 Question 2

Molodets [167]

Answer:

$\boxed{75 < x < 110 \: and \: 0 < y \leqslant 50}$

Step-by-step explanation:

x - the temperature

y - the number of people

the temperature is between 75 degrees and 110 degrees:

75 < x < 110

the room for 50 people:

0 < y ≤ 50

7 0

2 years ago

Read 2 more answers

∠E and ∠F are vertical angles with m∠E=8x+8 and m∠F=2x+38 . What is the value of x?

Zigmanuir [339]

We know that ∠E = ∠F because of the vertical angle theorem.

Using substitution we get 8x + 8 = 2x + 38

Solve for x.

8x + 8 = 2x + 38
8x = 2x = 30 <-- Subtract 8 from each side
6x = 30 <-- Subtract 2x from each side
x = 5 <-- Divide both sides by 6

So, x is equal to 5.

3 0

3 years ago