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lorasvet [3.4K]
2 years ago
12

Red and grey bricks were used to build a decorative wall. The number of red bricks/number of grey bricks was 5/2. There were 140

bricks used in all. How many red bricks were used?
20

40

100

28
Mathematics
1 answer:
Airida [17]2 years ago
6 0
To find the number of red bricks used, you can create a part to part to whole ratio from the simple ratio of red to grey brick they give.

Then, use the total to create an equivalent ratio with the actual total number of bricks (140).

<u>5 red </u>    <u>100 red</u>
<u>2 grey</u> =  <u>40 grey</u>
7 total   140 total
<u>
</u>Each time, the simple ratio was multiplied by 20 to get the actual totals for each color.
<u>
</u>There were 100 red bricks used.<u>


</u>
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Lynna [10]

The probabilities are:

  • P(red) = 5/24
  • P(orange) =  0
  • P(blue) =  1/3
  • P(not green)= 17/24
  • P(green or black) = 11/24
  • P(not yellow)  = 1.

<h3>How to find the probabilities?</h3>

The probability of getting a particular color of marble, is given by the quotient between the number of marbles of that color and the total number of marbles.

Here we have:

  • 5 red marbles.
  • 7 green marbles.
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  • 8 blue marbles.

So the total number is 5 + 7 + 4 + 8 = 24.

Then:

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  • P(not green) = (24 - 7)/24 = 17/24
  • P(green or black) = (4 + 7)/24 = 11/24
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If you want to learn more about probability, you can read:

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A car rental company charges, y, for x, days. Days 3 4 5 6
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The equation of the car rental company in the form y = kx is; y = 18.50x

The equation y = kx is such that;

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In essence; to determine the constant of proportionality, k in this case;

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Since the company charges, $55.50 for 3 days; we have;

By evaluation k = $55.50/3

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A researcher is testing a hypothesis of a single mean. The critical z value for a = .05 and a two‑tailed test is +1.96. The obse
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Answer:

The decision made by the researcher based on this information is to reject the null hypothesis.

Step-by-step explanation:

Two-tailed hypothesis test:

Critical value: z_c

Test statistic: z

If |z| < |z_c|, we do not reject the null hypothesis.

If |z| > |z_c|, we reject the null hypothesis.

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