3.04 , 3.14 , 3.4 , 4.03 , 4.4
Answer:
42.194988
Step-by-step explanation:
There are 42.194988 km in 1 marathon
487/67= 7.2686567
rounded= 7.269
The equivalent expression for [gofoh](9) is 5(32(9)^5-1).
According to the given question.
We have three functions
f(x) = x^5 - 1
g(x) = 5x^2
h(x) = 2x
Here, we have to find the equivalent expression for [gofoh](9).
so,
gofoh(x)
= g((2x)^5 -1)
= g(32x^5 -1)
= 5(32x^5 -1)
Therefore,
gofoh(9)
= 5(32(9)^5-1)
Hence, the equivalent expression for [gofoh](9) is 5(32(9)^5-1).
Find out more information about equiavlent expression here:
brainly.com/question/28170201
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We will conclude that:
- The domain of the exponential function is equal to the range of the logarithmic function.
- The domain of the logarithmic function is equal to the range of the exponential function.
<h3>
Comparing the domains and ranges.</h3>
Let's study the two functions.
The exponential function is given by:
f(x) = A*e^x
You can input any value of x in that function, so the domain is the set of all real numbers. And the value of x can't change the sign of the function, so, for example, if A is positive, the range will be:
y > 0.
For the logarithmic function we have:
g(x) = A*ln(x).
As you may know, only positive values can be used as arguments for the logarithmic function, while we know that:

So the range of the logarithmic function is the set of all real numbers.
<h3>So what we can conclude?</h3>
- The domain of the exponential function is equal to the range of the logarithmic function.
- The domain of the logarithmic function is equal to the range of the exponential function.
If you want to learn more about domains and ranges, you can read:
brainly.com/question/10197594