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nevsk [136]
3 years ago
8

Fill blanks with:N−Cα−C N − C α − CCα−C C α − CN−Cα N − C αbackboneside chaina stable secondary structurea stable tertiary struc

turea stable functionadoptchangeα−NH group α − N H groupα−COOH group α − C O O H groupH-bond donor H -bond donorelectron donordestabilizedstabilizedEach residue in a polypeptide chain has two backbone bonds: Each residue in a polypeptide chain has two backbone bonds: blank, about which rotation is permitted. The angle of rotation about the blank bond is referred to as ϕ (phi) and that about the blank bond is called ψ (psi).These angles describe the blank conformation of any particular residue in any protein, and allow one to predict whether a combination of amino acids in a polypeptide will be able to form and maintain blank. conformation of any particular residue in any protein, and allow one to predict whether a combination of amino acids in a polypeptide will be able to form and maintain blank.Proline is not able to blank the ideal ϕ and ψ angles for an α helix, owing to the presence of the rigid imidic group as its side chain.Furthermore, proline does not have an blank that acts as a stabilizing blank in the middle of the helix. As a consequence, the secondary structure is predicted to be blank..

Biology
1 answer:
polet [3.4K]3 years ago
3 0

Answer:

Explanation: see attachment below

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3 years ago
In a certain plant, tall stems (t) are dominant to short stems (t). a farmer crosses a short-stemmed plant with a heterozygous l
melisa1 [442]

The answers would be:

Genotype                Phenotype

     Tt                      Tall stemmed

     tt                       Short stemmed

Genotypic ratio : 2:2 or 1:1

Phenotypic ratio: 2:2  or 1:1  

<u />

<u>You can read on to see how this was done:</u>

Tall stems (T) are dominant to short stems (t).

First figure out the genotypes of the parents. We have a short-stemmed plant and a heterozygous long-stemmed plant cross.

For short stem to occur, you need 2 pairs of short alleles. So the first parent would have a genotype of tt.

Heterozygous long-stemmed means that the parent has one of each allele. So the genotype of the second parent would be, Tt.

Now we can make our Punnett Square.

tt x Tt

<u>       t        t  </u>

<u>T |  Tt  |   Tt</u>

<u>t  |   tt  |   tt</u>

Let's list down the genotypes and phenotypic results.

Genotype        no.         Phenotype

     Tt                 2           Tall stemmed

     tt                  2           Short stemmed

So from that we can answer the other questions:

Genotypic ratio : 2:2 or 1:1

Phenotypic ratio: 2:2  or 1:1  

8 0
3 years ago
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