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aleksley [76]
3 years ago
13

Y = 3x + 2 -4x + 2y = 8

Mathematics
1 answer:
Sergio [31]3 years ago
4 0

Answer: x=2 and y=8

Step-by-step explanation:see attachment

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If you earn $400 a week, what is your hourly wage?
Nata [24]

Answer:

2.38 dollars in a week

Step-by-step explanation:

168 hours = Week

400 dollars = Week

400 ÷ 168  = 2.38

5 0
2 years ago
Convert 1 cal/(m^2 * sec * °C) into BTU/(ft^2 * hr * °F)
Crazy boy [7]

Answer:

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

Step-by-step explanation:

To find : Convert 1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C} into \frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

Solution :

We convert units one by one,

1\text{ m}^2=10.7639\text{ ft}^2

1\text{ sec}=\frac{1}{3600}\text{ hour}

1\text{ cal}=0.003968\text{ BTU}

Converting temperature unit,

^\circ C\times \frac{9}{5}+32=^\circ F

1^\circ C\times \frac{9}{5}+32=33.8^\circ F

So, 1^\circ C=33.8^\circ F

Substitute all the values in the unit conversion,

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{10.7639\times \frac{1}{3600}\times 33.8}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{0.101061}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

Therefore, The conversion of unit is 1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

3 0
3 years ago
Find a5, when a1 =4, r=5
sasho [114]

Answer:

Answer: a5 = 2500

Step-by-step explanation:

For a geometric sequence:  

First term = a0  

Second term = a1 = a0*r  

Third term = a2 = a0*r^2  

Fourth term = a3 = a0*r^3  

....  

nth term = a(n-1) = a0*r^(n-1)  

Given: a1 = 4 = a0*r  

Also: r = 5  

So, a0*5 = 4 => a0 = (4/5)  

a5 = a(6-1) = Sixth term = a0*r^5 = (4/5)*5^5 = 2500  


Hope this helps

correct me if im wrong☺


3 0
3 years ago
The school band sold 3,305 raffle tickets to raise money for a trip to Disney World. Which equation shows the relationship betwe
Iteru [2.4K]
I believe it would be D.
4 0
3 years ago
Read 2 more answers
What is the probability of getting either a sum of 5 or at least one 5 in the roll of a pair of dice?
maria [59]
In a throw of 2 fair dice, there are 6*6=36 equiprobability outcomes.

To get a sum of 5, there are 4 ways, (1,4),(2,3),(3,2),(4,1) with probability of 4/36=1/9

To get at least one 5, there are 6+6-1=11 outcomes (note (5,5) has been counted in both, so subtracted from sum).  The probability is 11/36

Since the two events are mutually exclusive (once we have a five, the sum can no longer be 5), we can add the probabilities to get the probability of one event or the other.

P(sum of 5 OR at least one 5)=1/9+11/36=4/36+11/36=15/36=5/9
4 0
3 years ago
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