The answer would be D. Four groups
Fungi are usually classified in four divisions: the Chytridiomycota (chytrids), Zygomycota (bread molds), Ascomycota (yeasts and sac fungi), and the Basidiomycota (club fungi).
The question is incomplete as the options are not provided which are:
RNA replicase is present in the viral capsid.
The RNA genome is of the plus sense and RNA replicase is present in the viral capsid.
The new bacteriophage is a retrovirus.
The RNA genome is of the plus sense.
Answer:
The RNA genome is of the plus sense and RNA replicase is present in the viral capsid.
Explanation:
The bacteriophage is the virus particles which are composed of the genetic material enclosed in the Capsid protein. The Bacteriophage virus infects the bacteria and uses their replication machinery to replicate themselves.
In the given question, all the proteins along with RNA for translation or ribosomes is provided. The single-stranded RNA is first their genome copied by the RNA replicase and the positive strand, therefore, acts as the mRNA. This mRNA is then translated into the protein sequence and a new virion is produced.
Thus, the selected option is correct.
Answer:
Explanation:
<em>Let the ability to break down the red color in beets be represented by the allele </em><em>B</em><em>. The inability would be represented by the allele </em><em>b</em><em>.</em>
A nonsecretor's genotype would be BB or Bb while a secretor's genotype would be bb.
A nonsecretor woman with a secretor father would be a carrier with genotype Bb. A nonsecretor man who in a previous marriage had a secretor daughter would also be a carrier with genotype Bb. If the two marries:
<em>Bb x Bb</em>
<em> BB 2Bb bb</em>
1.
(a) probability of their first child will be a secretor girl = probability of having a girl and being a secretor.
Probability of having a girl = 1/2
Probability of being a secretor = 1/4
<em>probability of their first child will be a secretor girl</em> = 1/2 x 1/4 = 1/8
(b) Probability of their first child being a nonsecretor girl = probability of having a girl and being a nonsecretor.
Probability of having a girl = 1/2
Probability of being a nonsecretor = 3/4
<em>Probability of their first child being a nonsecretor girl = probability of having a girl and being a nonsecretor</em> = 1/2 x 3/4 = 3/8
2. <em>Probability that their first two children will be nonsecretors of either sex = probability of their first being a nonsecretor and of either sex and probability of their second being a nonsecretor and of either sex.</em>
= 3/4 x 3/4 = 9/16
Answer:
Pacific Northwest
Explanation:
Because u can look it up on the map to see if u are right or wrong