Disregarding air friction, the distance traveled by an object due to gravity is : H = 0.5*g*t^2. g is the gravitational constant at the surface of earth.
g= 9.81 m/s^2
After 3 seconds, Distance = .5*9.81*9 = 44.15 meters traveled.
Since it was dropped from a height of 90 meters, the current height is 90 - 44.15 = (a) 45.85 meters
(b) It has to travel 90 meters to hit the ground . So we must find t
Using the same equation
t = (2*H/g)^.5
t = (2*90/g)^.5 = 4.28 seconds until it hits the ground
Answer:
first collect the like terms so that you have -4x is equals to -2 - 26 then negative 4x is equals to -28 divided by -4x is equals to 7
Answer:
Base = 4.62m, Height = 6.93m
Step-by-step explanation:
I worked through the black first, then went to the blue.
The equation of line passing through the point P(-8,0) that is perpendicular to the line y=-3 is y=0 which can be found out from slope intercept formula.
It is given to us that -
The point is P(-8,0)
The line is represented as y=-3
The point P is perpendicular to the given line.
We have to find out the equation of the line passing through P which is perpendicular to the given line.
We know that the equation of a line is given by -
y = mx + c
where, (x, y) = coordinates of the point
m = slope of the line
c = a constant
Comparing this with the equation of the given line, we have
m=0 and c =-3
This implies that the slope of the perpendicular is also equal to 0.
The slope intercept formula for the perpendicular line can be represented as -
y = mx + c
Using the coordinates of P(-8,0), we have
0 = 0*(-8) +c
=> c = 0.
Thus, the equation of line passing through the point P(-8,0) that is perpendicular to the line y=-3 is y=0.
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