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Delicious77 [7]
3 years ago
11

Tom drops a coin from the top of a building. Tom is 90 meters from the ground when he drops the coin. A) What is the height of t

he coin exactly 3 seconds after he releases the coin? B) When the coin hits the ground, how much time has passed from when it was dropped until impact with the ground?
Mathematics
1 answer:
Delvig [45]3 years ago
3 0
Disregarding air friction, the distance traveled by an object due to gravity is : H = 0.5*g*t^2.   g is the gravitational constant at the surface of earth.  

g= 9.81 m/s^2  

After 3 seconds, Distance = .5*9.81*9 = 44.15 meters traveled.   

Since it was dropped from a height of 90 meters, the current height is 90 - 44.15 = (a) 45.85 meters  

(b) It has to travel 90 meters to hit the ground . So we must find t  

Using the same equation  

t = (2*H/g)^.5 

 t = (2*90/g)^.5 = 4.28 seconds until it hits the ground
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I think it wants you to multiply the numbers.
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Final Answer=2632
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3 years ago
Read 2 more answers
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