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mina [271]
3 years ago
13

What is 2x-{2-[2(x-2)-(2-x)]}=0

Mathematics
1 answer:
Ludmilka [50]3 years ago
3 0
2x-(2-(2(x-2)-(2-x)))=0\\
2x-(2-(2x-4-2+x))=0\\
2x-(2-(3x-6))=0\\2x-(2-3x+6)=0\\
2x-(-3x+8)=0\\
2x+3x-8=0\\
5x=8\\
x=\dfrac{8}{5}
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