Question

What is 2x-{2-[2(x-2)-(2-x)]}=0

Answer 1

$2x-(2-(2(x-2)-(2-x)))=0\\ 2x-(2-(2x-4-2+x))=0\\ 2x-(2-(3x-6))=0\\2x-(2-3x+6)=0\\ 2x-(-3x+8)=0\\ 2x+3x-8=0\\ 5x=8\\ x=\dfrac{8}{5}$