3 years ago

What is 2x-{2-[2(x-2)-(2-x)]}=0

1 answer:

3 0

$2x-(2-(2(x-2)-(2-x)))=0\\
2x-(2-(2x-4-2+x))=0\\
2x-(2-(3x-6))=0\\2x-(2-3x+6)=0\\
2x-(-3x+8)=0\\
2x+3x-8=0\\
5x=8\\
x=\dfrac{8}{5}$

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3 years ago

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3 years ago

2y+4x=8 when x=-2,1,3

kondor19780726 [428]

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When x = 1:   4x + 2y = 8
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3 years ago