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3 years ago

15

A triangle has one angle that measures 40degrees and another angle that measures 38 degrees. What is the measure of the triangle

s third angle?
A)12
B)102
C)78
D)178

2 answers:

vredina [299]3 years ago

8 0

The measurement of the triangles third side is 78 !

g100num [7]3 years ago

8 0

Answer:

B)102 because 40+38=78 and the total degrees for a triangle is 180° , there for 180-78=102

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A segment has an endpoint at (1,−2). The midpoint is at (−4,−2). What are the coordinates of the other endpoint?

vodka [1.7K]

Answer:

The other midpoint is located at coordinates (-9,-2) (Second option)

Step-by-step explanation:

<u>Midpoints</u>

If P(a,b) and Q(c,d) are points in $\mathbb{R} ^2$ , the midpoint between them is the point exactly in the center of the line that joins P and Q. Its coordinates are given by

$\displaystyle x_m=\frac{a+c}{2}$

$\displaystyle y_m=\frac{b+d}{2}$

We are given one endpoint at P(1,-2) and the midpoint at M(-4,-2). The other endpoint must be at an equal distance from the midpoint as it is from P. We can see both given points have the same value of y=-2. This simplifies the calculations because we only need to deal with the x-coordinate.

The x-distance from P to M is 1-(-4)=5 units. This means the other endpoint must be 5 units to the left of M:

x (other endpoint)= - 4 - 5 = - 9

So the other midpoint is located at (-9,-2) (Second option)

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3 years ago

To be considered similar, two polygons must have corresponding sides that are in proportion.

Agata [3.3K]

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3 years ago

I can’t figure out how to use the zeros in the polynomial. Please explain

Temka [501]

Answer:

a) $P (x) = (x + 3) (x-1) (x-4)$

b) $P (x) = (2x + 5) (5x - 4) (x-6)$

c) $P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2$

Step-by-step explanation:

<u>For the question a *</u> you need to find a polynomial of degree 3 with zeros in -3, 1 and 4.

This means that the polynomial P(x) must be zero when x = -3, x = 1 and x = 4.

Then write the polynomial in factored form.

$P (x) = (x + 3) (x-1) (x-4)$

Note that this polynomial has degree 3 and is zero at x = -3, x = 1 and x = 4.

<u>For question b, do the same procedure</u>.

Degree: 3

Zeros: -5/2, 4/5, 6.

The factors are

$x = -\frac{5}{2}\\\\x +\frac{5}{2} = 0\\\\(2x +5) = 0$

---------------------------------------

$x =\frac{4}{5}\\\\x-\frac{4}{5} = 0\\\\(5x-4) = 0$

--------------------------------------

$x = 6\\\\(x-6) = 0$

--------------------------------------

$P (x) = (2x + 5) (5x - 4) (x-6)$

<u>Finally for the question c we have</u>

Degree: 5

Zeros: -3, 1, 4, -1

Multiplicity 2 in -1

$x = -3\\\\(x-3) = 0$

--------------------------------------

$x = 1\\\\(x-1) = 0$

--------------------------------------

$x = 4\\\\(x-4) = 0$

----------------------------------------

$x = -1\\\\(x + 1) = 0$

-----------------------------------------

$P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2$

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3 years ago

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Basically solve for y
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3 years ago

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Tanya [424]

Answer:

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b - 20

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Step-by-step explanation:

20 x .4 = 8

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3 years ago

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