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notka56 [123]
3 years ago
10

Holiday Time! Crazy Time! You have to work 7 days in a row. You work 8 hours a day every single day for 7 days straight. Your wa

ge rate is $12 per hour. How much are your gross wages?
Mathematics
2 answers:
Ulleksa [173]3 years ago
8 0
I think its 672 because * hrs a day is 56 and when you multiply that by 12 its 672<span />
algol133 years ago
8 0
So if you work 7 hours a day for 8 days in a row we get 56 hours, then multiply that by $12 to find your earnings which is 672.
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Solve F=D+Drt for t.....
Anuta_ua [19.1K]

Answer:

t = \frac{-D+F}{Dr}

Step-by-step explanation:

Step 1: Flip the equation.

  • Drt + D = F

Step 2: Subtract D from both sides.

  • Drt + D - D = F - D
  • Drt = -D + F

Step 3: Divide both sides by Dr.

  • \frac{Drt}{Dr} = \frac{-D+F}{Dr}
  • t = \frac{-D+F}{Dr}

6 0
2 years ago
Find the Volume. Plz Help
koban [17]

Answer:

B

Step-by-step explanation:

V = \frac{l*w*h}{2} = \frac{18*12*9}{2} = \frac{1944}{2} = 972

3 0
3 years ago
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A quality control expert at Glotech computers wants to test their new monitors. The production manager claims they have a mean l
tankabanditka [31]

Answer:

The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors

P(X⁻ ≥ 96.3) = 0.0087

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the mean of the Population = 95

Given that the standard deviation of the Population = 5

Let 'X' be the random variable in a normal distribution

Let X⁻ = 96.3

Given that the size 'n' = 84 monitors

<u><em>Step(ii):-</em></u>

<u><em>The Empirical rule</em></u>

         Z = \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } }

        Z = \frac{96.3 - 95}{\frac{5}{\sqrt{84} } }

       Z = 2.383

The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors

    P(X⁻ ≥ 96.3) = P(Z≥2.383)

                      =  1- P( Z<2.383)

                      =  1-( 0.5 -+A(2.38))

                      = 0.5 - A(2.38)

                     = 0.5 -0.4913

                    = 0.0087

<u><em>Final answer:-</em></u>

The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors

P(X⁻ ≥ 96.3) = 0.0087

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Who replaced circles with ellipses in a heliocentric model of the universe
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10(4x-1) is the answer to your question my friend

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