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Semenov [28]
3 years ago
9

A line passing through which of the following pairs of coordinates represents a proportional relationship?

Mathematics
2 answers:
Hoochie [10]3 years ago
7 0
D since the y-intercept would be (0,0), which means that it starts from the origin.
(haha I misread option A and B)


sasho [114]3 years ago
6 0

Answer:

<h2>D. (3, 6) and (4, 8)</h2>

Step-by-step explanation:

A proportion relation is defined as two variables that interact one to each other, directly. Basically its definition could be

y=kx

This means that the set of points must have a constant proportion k.

However, in this case we only have one pair of points. A specific characteristic of proportional relationship in this case is that such ratio is a whole number: ±1, ±2, ±3, ±4, ±5,... ±n.

In this case, the last pair of point fulfil this characteristic. We demonstrate that by finding the ratio, which is the slope of the linear relationship

m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }

Where (x_{1} ,y_{1} ) is the first point and (x_{2} ,y_{2} ) is the second point. Replacing these points, we have

m=\frac{8-6}{4-3}=\frac{2}{1}=2

So option D has a proportional relationship with a constant ratio of 2.

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1. The diameter of a sphere is 21.6 cm. The volume of the sphere is __
sveta [45]
Detailed Answers:

Volume of a Sphere (V) = 4/3 πr^3

1. Diameter (d) = 21.6 cm
Radius (r) = 21.6/2 = 10.8 cm

Therefore,
= 4/3 πr^3
= 4/3 * 22/7 * (10.8)^3
= 4/3 * 22/7 * 1259.712
= 88/21 * 1259.712
=> 5278.79

Volume (V) = 5278.79 cm^3

2. Diameter (d) = 16 cm
Radius (r) = 16/2 = 8 cm

Therefore,
= 4/3 πr^3
= 4/3 * 22/7 * (8)^3
= 4/3 * 22/7 * 512
= 88/21 * 512
=> 2145.52

Volume (V) = 2145.52 cm^3

3. Diameter (d) = 24 cm
Radius (r) = 24/2 = 12 cm

Therefore,
= 4/3 πr^3
= 4/3 * 22/7 * (12)^3
= 4/3 * 22/7 * 1728
= 88/21 * 1728
=> 7241.14

Volume (V) = 7241.14 cm^3

4. Diameter (d) = 6 cm
Radius (r) = 6/2 = 3 cm

Therefore,
= 4/3 πr^3
= 4/3 * 22/7 * (3)^3
= 4/3 * 22/7 * 27
= 88/21 * 27
=> 113.14

Volume (V) = 113.14 cm^3
6 0
1 year ago
Read 2 more answers
What are the domain and range of the inequality y &lt; sqrt x+3+1
love history [14]

Given:

The inequality is:

y

To find:

The domain and range of the given inequality.

Solution:

We have,

y

The related equation is:

y=\sqrt{x+3}+1

This equation is defined if:

x+3\geq 0

x\geq -3

In the given inequality, the sign of inequality is <, it means the points on the boundary line are not included in the solution set. Thus, -3 is not included in the domain.

So, the domain of the given inequality is x>-3.

We know that,

\sqrt{x+3}\geq 0

\sqrt{x+3}+1\geq 0+1

y\geq 1

The points on the boundary line are not included in the solution set. Thus, 1 is not included in the range.

So, the domain of the given inequality is y>1.

Therefore, the correct option is A.

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3 years ago
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Alona [7]

Answer:54?

Step-by-step explanation:

5 0
3 years ago
Scientific Notation
Katarina [22]
3.615 x 10^2 i hope this helps

3 0
2 years ago
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Solve for 15 ≥ -3x or x ≥ -2.
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Answer:

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Step-by-step explanation:

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