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Semenov [28]
3 years ago
9

A line passing through which of the following pairs of coordinates represents a proportional relationship?

Mathematics
2 answers:
Hoochie [10]3 years ago
7 0
D since the y-intercept would be (0,0), which means that it starts from the origin.
(haha I misread option A and B)


sasho [114]3 years ago
6 0

Answer:

<h2>D. (3, 6) and (4, 8)</h2>

Step-by-step explanation:

A proportion relation is defined as two variables that interact one to each other, directly. Basically its definition could be

y=kx

This means that the set of points must have a constant proportion k.

However, in this case we only have one pair of points. A specific characteristic of proportional relationship in this case is that such ratio is a whole number: ±1, ±2, ±3, ±4, ±5,... ±n.

In this case, the last pair of point fulfil this characteristic. We demonstrate that by finding the ratio, which is the slope of the linear relationship

m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }

Where (x_{1} ,y_{1} ) is the first point and (x_{2} ,y_{2} ) is the second point. Replacing these points, we have

m=\frac{8-6}{4-3}=\frac{2}{1}=2

So option D has a proportional relationship with a constant ratio of 2.

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Step-by-step explanation:

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aleksandrvk [35]

Answer:

Part 1) FG=4.4\ units

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Part 3) m\angle G=63^o

Step-by-step explanation:

step 1

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In the right triangle EFG

we know that

sin(27^o)=\frac{GE}{FG} ----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

sin(27^o)=\frac{2}{FG}

FG=\frac{2}{sin(27^o)}=4.4\ units

step 2

Find the measure of length side EF

In the right triangle EFG

we know that

cos(27^o)=\frac{EF}{FG} ----> by CAH (adjacent side divided by the hypotenuse)

substitute the given values

cos(27^o)=\frac{EF}{4.4}

EF=cos(27^o)(4.4)=3.9\ units

step 3

Find the measure of angle G

we know that

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Step 2: Interchange x and y.

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Hence, the inverse of the given function is g(x)=\dfrac{5-x}{2} and the graphs of these functions are shown below.

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