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4 years ago

For what numbers x, -2π ≤ x ≤ 2π, does the graph of y = csc(x) have vertical asymptotes?

1 answer:

8 0

Well tan x has asymptotes every 90 degrees, or in radian mode, every pi divided by two. since cot is the inverse and the aymsptotes land on every 180 degrees, meaning the equation can be x ≠ \pi n, nEI

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Paladinen [302]

Answer:

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Step-by-step explanation:

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8 0

2 years ago

What are the properties of real numbers?

expeople1 [14]

Https://mathbitsnotebook.com/Algebra1/RealNumbers/RNProp.html

3 0

3 years ago

Help me help me answer this

Leya [2.2K]

If both triangles are congruent (that's what the sign means), then AD=CB, and CD=AB. Substituting what we are given into CD=AB,

6x-5=3x+10

Solving the equation:

3x=15

x=5

So we know that 2x+4 (the value of AD) becomes 2*5 +4, and you get 14. Since we know that AD=CB, then CB is also 14. No need to find y!

Answer: CB=14

8 0

3 years ago

A triangle has base 2x+1 and height 6x-3. What value of x would give an area of 240m2?

GREYUIT [131]

Answer:

The values of x which would give an area of 240m² would be:

$x=-\frac{\sqrt{161}}{2},\:x=\frac{\sqrt{161}}{2}$

Step-by-step explanation:

Given

The base of triangle b = 2x+1

The height of triangle h = 6x-3

The Area of the triangle A = 240 m²

The Area of the triangle has the formula

A = 1/2 × b × h

substituting b = 2x+1, h = 6x-3 and A = 240

$240\:=\:\frac{1}{2}\:\left(2x+1\right)\:\times \left(6x-3\right)$

$480=\left(2x+1\right)\left(6x-3\right)$

$480=12x^2-3$

Subtract 480 from both sides

$12x^2-3-480=480-480$

$12x^2-483=0$

$3\left(4x^2-161\right)=0$

$3\left(2x+\sqrt{161}\right)\left(2x-\sqrt{161}\right)=0$

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

$2x+\sqrt{161}=0\quad \mathrm{or}\quad \:2x-\sqrt{161}=0$

solving

$2x+\sqrt{161}=0$

$2x=-\sqrt{161}$

Divide both sides by 2

$\frac{2x}{2}=\frac{-\sqrt{161}}{2}$

$x=-\frac{\sqrt{161}}{2}$

also solving

$2x-\sqrt{161}=0$

$2x=\sqrt{161}$

Divide both sides by 2

$\frac{2x}{2}=\frac{\sqrt{161}}{2}$

$x=\frac{\sqrt{161}}{2}$

Therefore, the values of x which would give an area of 240m² would be:

$x=-\frac{\sqrt{161}}{2},\:x=\frac{\sqrt{161}}{2}$

3 0

3 years ago

On a coordinate plane, the fountain is at (7, 5), the gardens are at (3, negative 5), the pond is at (negative 1, 7), and conces

kogti [31]

Answer:

The guy above me was rude. The answer is A, C, D. I just got it right on my assignment.

Step-by-step explanation:

For the meme: no

5 0

3 years ago

Read 2 more answers