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3 years ago

The table shows the grade that 4 students received on a math test. Find the bar graph that represents the grades.

Mathematics

1 answer:

tiny-mole [99]3 years ago

6 0

Answer:

The answer to your question is the first graph.

Step-by-step explanation:

It seems that the first graph is correct because the height of the bars is equal to the grade get by the students.

The second graph is incorrect because the height of the bars is different from the grade the students got. Only the bar of Levi is correct.

The third graph is incorrect, just observe the height of John's bar to determine that the graph is wrong.

Also, the last graph is incorrect, in this graph, all the bars are different from the grade the students got.

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A drawing of a surfboard in a catalog, it shows its length as 8 4/9 inches. Find the actual length of the surfboard if 1/3 inch

Bond [772]

Answer:

9.5 feets

Step-by-step explanation:

Length of drawing = 8 4/9 inches

Scale : 1/3 inch in drawing = 3/8 actual length

Length of drawing / drawing scale

8 4/9 = 76/9 inches

Number of 1/3 inches in total length of drawing :

76/9 ÷ 1/3

76/9 * 3 / 1

(76*3) /(9*1) = 228 /9 = 9 3/9 = 9 1/3

9 1/3 * 3/8 foot

(228 / 9) * (3 /8)

(228/3) * (1/ 8)

228 / 24

= 9.5 feet

4 0

2 years ago

Write (x+7)(x−2) as a sum

Dennis_Churaev [7]

Answer:

x^2+5x-14

Step-by-step explanation:

you multiply both equations so that you get:

x^2-2x+7x-14

and then you simplify it to:

x^2+5x-14

If you found this helpful please give it a thanks

I would also appreciate it if you give me a brainliest

8 0

2 years ago

If I'm doing it wrong correct me please but can you finish the rest for me idk how to

nevsk [136]

Sorry Im in 6th but i still have no idea......

4 0

3 years ago

Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)

Dima020 [189]

Split $C$ into two component segments, $C_1$ and $C_2$ , parameterized by

$\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)$

$\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)$

respectively, with $0\le t\le1$ , where $\mathbf r_i(t)=(x(t),y(t))$ .

We have

$\mathrm d\mathbf r_1=(6,1)\,\mathrm dt$

$\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt$

where $\mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt$

so the line integral becomes

$\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)$

$=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt$

$=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6$

6 0

2 years ago

What is 48 times 3 I'm giving y'all an easy chance for points answer is 144 I think

ch4aika [34]

Answer:

yup you are correct. The answer is 144 :)

Step-by-step explanation:

Also thx for the points!

3 0

2 years ago

Read 2 more answers