17. What are the minimum, first quartile, median, third quartile, and maximum of the data set? 40, 7, 2, 35, 12, 23, 18, 28
Rzqust [24]
First step! Arrange the numerals {<span>40, 7, 2, 35, 12, 23, 18, 28} in ascending order: {2, 7, 12, 18, 23, 28, 35, 40}
Count these numerals: there are 8 (an even number)
To find the median of this set of numerals, take the middle 2 values {18, 23} and average them: median = (18+23)/2 = 41/2
Now, on the left of 41/2, we have the subset {2, 7 , 12, 18}. The median of this subset is found in the same way as was 41/2 (above):
(7+12)/2 = 19/2 (First quartile)
The median of the right subset {</span>23, 28, 35, 40} is (28+35)/2, or 63/2. This is the 3rd quartile.
The max. is 40 (this is the largest numeral given).
So (31 and 3/4) times (4) plus ( 18 and 5/6) times (6)
Remember
P
E
M
D
A
S
so [(31 and 3/4) times * (4)] + [ (18 and 5/6 ) times (6)]
that is [127] + [113]
so is 240
Hope this helps ;)
Answer:
c = 3 / a − b + 2
Explanation:
[ Step 1: Multiply both sides by c ]
ac = bc − 2c + 3
[ Step 2: Add -bc to both sides ]
ac + −bc = bc − 2c + 3 + −bc
ac − bc = −2c + 3
[ Step 3: Add 2c to both sides ]
ac − bc + 2c = −2c + 3 + 2c
ac − bc + 2c = 3
[ Step 4: Factor out variable c ]
c(a − b + 2) = 3
[ Step 5: Divide both sides by a - b + 2 ]
c(a − b + 2) / a − b + 2 = 3 / a − b + 2
c = 3 / a − b + 2
Answer:
17
Step-by-step explanation:
-3n-24n+18n-9n+36n-n = +17