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Vinvika [58]
3 years ago
10

The Orchard Pie company uses 95 pounds of apples. How many pounds of apples are used in each pie?

Mathematics
1 answer:
Elza [17]3 years ago
6 0
Question is number 16

95 ÷ 100 = .95
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A line is represented by the equation y=3x+5. what are the coordinates
VARVARA [1.3K]
The 3x is the x axis and the y is 5 so it would be (3,5).
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What additional information do you need to prove that ∆LMO ≅ ∆LNO by the HL Theorem? ∠NLO ≅ ∠MLO ∠MOL ≅ ∠NOL
FromTheMoon [43]
The hypotenuse leg theorem states that any two right triangles that have a congruent hypotenuse and a corresponding, congruent leg are congruent triangles.
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Which is greater 6km, 60m, 600cm, or 6000 mm
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The answer is 6km 

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3 years ago
At a college campus, random drug tests are carried out to prevent use of prohibited drugs by athletes. Of all the athletes on ca
saw5 [17]

Answer:

a) 0.3064 = 30.64% probability that athlete will test positive for prohibited drug use.

b) 0.2693 = 26.93% probability that this drug user never used the prohibited drug.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

A. If an athlete is selected at random, what is the probability that athlete will test positive for prohibited drug use?

100 - 5 = 95% of 8%

100 - 13 = 87% of 17%

11% of 75%

So

p = 0.95*0.08 + 0.87*0.17 + 0.11*0.75 = 0.3064

0.3064 = 30.64% probability that athlete will test positive for prohibited drug use.

B. If an athlete tests positive after a drug test, what is the probability that this drug user never used the prohibited drug?

Conditional Probability

Event A: Tests Positive

Event B: Never used the drug.

0.3064 = 30.64% probability that athlete will test positive for prohibited drug use

This means that P(A) = 0.3064

Probability of testing positive while never using the drug.

11% of 75%. So

P(A \cap B) = 0.11*0.75 = 0.0825

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0825}{0.3064} = 0.2693

0.2693 = 26.93% probability that this drug user never used the prohibited drug.

8 0
3 years ago
Gary has 9 quarts of paint. If He Uses Half How Much gallons will he have.
Anna007 [38]

Answer:

1.125 gallons

Step-by-step explanation:

The first thing you do here is convert 9 quarts to gallons. To convert from quarts to gallons you dvide by 4. So 9/4=2.25.

The next thing you do is divide this number by two to achieve your answer

2.25/2=1.125

So the final answer you would be after using half of his paint Gary is left with 1.125 gallons of paint

6 0
3 years ago
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