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topjm [15]
3 years ago
11

What additional information will allow you to prove the triangles congruent by the HL Theorem? Please show your work.

Mathematics
1 answer:
prisoha [69]3 years ago
3 0
You ca also use sss, sas, asa, aas, and that, hl.
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Simplify <br> (^3)x4<br> Easy 30 points
aleksklad [387]

Answer:

=81

Step-by-step explanation:

\left(-3\right)^4

Use exponent rule \left(-a\right)^n=a^n:

=3^4

=81

5 0
3 years ago
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Simplify this question
Serhud [2]

Step-by-step explanation:

9x²/3x + 12x/3x + 1

= 3x/1 + 4/1 + 1

= 3x + 5

I hope this is true..

8 0
2 years ago
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Im having a hard time on this question and I hope you can help.
Masja [62]

The answer would be x ≠ 0

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

First start with the left side, doing distributive property

So... -2(x) = -2x and -2(5) = -10 Therefore on the left side you now have -2x -10

Next do the same on the right side

-2(x) = - 2x and -2(-2) = 4 so you have -2x + 4 + 5 and you add 4 and 5, leaving you with -2x + 9

Now that you have simplified both sides the problem now looks like this:

-2x - 10 = -2x + 9

Because you have equal terms on both sides (-2) those cancel out so you have -10 = 9

Just from looking at this we know that the statement is false because -1o does not equal 9

*The symbol, "≠" means not equal to"

3 0
3 years ago
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How do you simplify expressions with rational exponents
Rainbow [258]

Answer:

Step-by-step explanation:

Simplify expression with rational exponents can look like a huge thing when you first see them with those fractions sitting up there in the exponent but let's remember our properties for dealing with exponents. We can apply those with fractions as well.

Examples

(a)   (p^4)^{\dfrac{3}{2}}

From above, we have a power to a power, so, we can think of multiplying the exponents.

i.e.

(p^{^ {\dfrac{4}{1}}})^{\dfrac{3}{2}}

(p^{^ {\dfrac{12}{2}}})

Let's recall that when we are dealing with exponents that are fractions, we can simplify them just like normal fractions.

SO;

(p^{^ {\dfrac{12}{2}}})

= (p^{ 6})

Let's take a look at another example

\Bigg (27x^{^\Big{6}} \Bigg) ^{{\dfrac{5}{3}}}

Here, we apply the \dfrac{5}{3} to both 27 and x^6

= \Bigg (27^{{\dfrac{5}{3}}} \times x^\Big{\dfrac{6}{1}\times {{\dfrac{5}{3}}} }\Bigg)

= \Bigg (27^{{\dfrac{5}{3}}} \times x^\Big{\dfrac{2}{1}\times {{\dfrac{5}{1}}} }\Bigg)

Let us recall that in the rational exponent, the denominator is the root and the numerator is the exponent of such a particular number.

∴

= \Bigg (\sqrt[3]{27}^{5} \times x^{10} }\Bigg)

= \Bigg (3^{5} \times x^{10} }\Bigg)

= 249x^{10}

8 0
3 years ago
A square has a diagonal length of 5 cm. The area of the squareiscm2. Round answer to the nearest tenths ifneeded.
Whitepunk [10]
\begin{gathered} \text{Diagonal}=5\operatorname{cm} \\ \text{Area}=\frac{D^2}{2} \\  \\ \text{Area}=\frac{(5cm)^2}{2} \\  \\ \text{Area}=\frac{25\operatorname{cm}^2}{2} \\  \\ \text{Area}=12.5\operatorname{cm}^2 \\ \text{The area of the square is 12.5 cm }^2 \end{gathered}

6 0
1 year ago
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