Ask question

Ask question

All categories

3 years ago

11

What additional information will allow you to prove the triangles congruent by the HL Theorem? Please show your work.

1 answer:

prisoha [69]3 years ago

3 0

You ca also use sss, sas, asa, aas, and that, hl.

You might be interested in

Red bricks and grey bricks were used to build a decorative wall. The number of red bricks divided by number of grey bricks was 5

azamat

Red bricks : Grey bricks
5 : 2

Total parts = 5 + 2 = 7

7 parts = 224
-----------------------
Find 1 part:
-----------------------
1 part = 234 ÷ 7
1 part = 32

-----------------------
Find 5 parts:
-----------------------
5 parts = 32 x 5
5 parts = 160

----------------------------------------------
Answer: 160 Red bricks
----------------------------------------------

5 0

3 years ago

Some body can help me with a geometric mean maze

Mars2501 [29]

Answer:

See explanation

Step-by-step explanation:

Theorem 1: The length of the altitude to the hypotenuse of a right triangle is the geometric mean of the lengths of the segments of the hypotenuse.

Theorem 2: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

1. Start point: By the 1st theorem,

$x^2=25\cdot (49-25)=25\cdot 24=5^2\cdot 2^2\cdot 6\Rightarrow x=5\cdot 2\cdot \sqrt{6}=10\sqrt{6}.$

2. South-East point from the Start: By the 2nd theorem,

$x^2=40\cdot (40+5)=4\cdot 5\cdot 2\cdot 9\cdot 5\Rightarrow x=2\cdot 5\cdot 3\cdot \sqrt{2}=30\sqrt{2}.$

3. West point from the previous: By the 2nd theorem,

$x^2=(32-20)\cdot 32=4\cdot 3\cdot 16\cdot 2\Rightarrow x=2\cdot 4\cdot \sqrt{6}=8\sqrt{6}.$

4. West point from the previous: By the 1st theorem,

$9^2=x\cdot 15\Rightarrow x=\dfrac{81}{15}=\dfrac{27}{5}=5.4.$

5. West point from the previous: By the 2nd theorem,

$10^2=8\cdot (8+x)\Rightarrow 8+x=12.5,\ x=4.5.$

6. North point from the previous: By the 1st theorem,

$x^2=48\cdot 6=6\cdot 4\cdot 2\cdot 6\Rightarrow x=6\cdot 2\cdot \sqrt{2}=12\sqrt{2}.$

7. East point from the previous: By the 2nd theorem,

$x^2=22.5\cdot 30=225\cdot 3\Rightarrow x=15\sqrt{3}.$

8. North point from the previous: By the 1st theorem,

$x^2=7.5\cdot 36=270\Rightarrow x=3\sqrt{30}.$

8. West point from the previous: By the 2nd theorem,

$x^2=12.5\cdot (12.5+13.5)=12.5\cdot 26=25\cdot 13\Rightarrow x=5\sqrt{13}.$

9. North point from the previous: By the 1st theorem,

$12^2=x\cdot 30\Rightarrow x=\dfrac{144}{30}=4.8.$

101. East point from the previous: By the 1st theorem,

$6^2=1.6\cdot (x-1.6)\Rightarrow x-1.6=22.5,\ x=24.1.$

11. East point from the previous: By the 2nd theorem,

$20^2=32\cdot (32-x)\Rightarrow 32-x=12.5,\ x=19.5.$

12. South-east point from the previous: By the 2nd theorem,

$18^2=x\cdot 21.6\Rightarrow x=15.$

13. North point=The end.

6 0

3 years ago

What is the degree of the power function represented in the<br> table?

Sonja [21]

Answer:

im in the same question as you bro

Step-by-step explanation:

5 0

3 years ago

I GIVEEEE BRAINLILSTT

Zigmanuir [339]

Alr bet x + 8 y - 9 :)

6 0

3 years ago

When given Three points on a coordinate plane, you may be able to find a specific Quadratic equation that intersects all given p

ohaa [14]

Answer:

TRUE

Step-by-step explanation:

A quadratic equation can be found that will go through any three distinct points that ...

satisfy the requirements for a function
are not on the same line

_____

The key word here is "may." You will not be able to find a quadratic intersecting the three points if they do not meet both requirements above.

8 0

3 years ago