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steposvetlana [31]
3 years ago
9

Help please .. what the answer?

Physics
1 answer:
umka2103 [35]3 years ago
3 0

As it is given here that two blocks are pulled towards right side with constant horizontal velocity.

Both blocks are given that moving with speed 2 m/s

Now we can say that by Newton's II law

F = ma

i.e. Net force on a system is product of its mass and acceleration

but as we can see that here two blocks are moving with  constant speed so here as per definition of acceleration we will say

a = \frac{dv}{dt}

As we know that v = constant

a = 0

so here from 2nd law

F = 0

so net force must be zero  block A

So correct FBD must be "option A"

we should not represent any force on it

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3 years ago
A block has a volume of 0.09 m3 and a density of 4,000 kg/m3. What's the force of gravity acting on the block in water?
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                                       Density = (mass) / (volume)

                                4,000 kg/m³ = (mass) / (0.09 m³)

Multiply each side
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                                 mass = 360 kg .

Force of gravity = (mass) x (acceleration of gravity)

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                           =   3,528 newtons . 

That's the force of gravity on this block, and it doesn't matter
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Now, it won't seem that heavy when it's in the water, because
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The block is displacing 0.09 m³ of water.  Water has 1,000 kg of
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5 0
4 years ago
Read 2 more answers
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Answer:

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Explanation:

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3 0
3 years ago
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Answer:

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Explanation:

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We can reasonably assume that the cart will have constant mass in the given force system.  With this assumption we can say the following relationship:

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Given that our force on the cart is doubled, then our acceleration of the cart must also be doubled.  You can mathematically express this as follows:

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