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2 years ago

In one to two sentences, explain why electromagnetic radiation can be modeled as both a wave and a particle.

Physics

1 answer:

kirill115 [55]2 years ago

4 0

Answer:

The answer is below!!

Explanation:

Electromagnetic radiation (e.g., radio, microwaves, light) can be modeled as a wave of changing electric and magnetic fields or as particles called photons. The wave model is useful for explaining many features of electro-magnetic radiation, and the particle model explains other features.

Hope I Helped!!

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A 12 V battery applies a potential difference to three resistors in series. If the potential at point P is 0.0 V, the potential

galina1969 [7]

This question is incomplete, the complete question is on the image uploaded along this answer.

Answer:

the potential at point B is 5 V, Option d) is the correct answer

Explanation:

Given that;

from the image;

R = 3 + 4 + 5 = 12 Ω

so I = 12/12 = 1 A

Q = 0 + 12 = 12 V

now

VA - VQ = - I × 3 = -3 V

VA = VQ - 3 = 12 - 3 = 9 V

VB - VA = - I × 4Ω = - 4 V

⇒VB = VA - 4 = 9 V - 4 V = 5 V

Therefore the potential at point B is 5 V

Option d) is the correct answer

4 0

3 years ago

At a rock concert, the sound intensity 1.0m in front of the bank of loudspeakers is 0.10 W/m^2. A fan is 30.0m from the loudspea

ElenaW [278]

Answer: The amount of energy transferred to each eardrum in one second is $6.2 \times 10^{-9} J$ .

Explanation:

Given: Intensity = 0.10 $W/m^{2}$

Now, at 30.0 m the intensity will be calculated as follows.

$Intensity = \frac{(30.0 m)^{2}}{(1 m)^{2}}\\= 900$

This means that the intensity is 900 times less assuming that the wave is spherical.

Hence, the new intensity is calculated as follows.

$\frac{0.10 W/m^{2}}{900}\\= 1.11 \times 10^{-4} W/m^{2}$

The area of ear drum is expressed as follows.

$Area = \pi \times r^{2}\\= 3.14 \times (4.2 mm)^{2}\\= 5.54 \times 10^{-5} m^{2}\\$

Formula used to calculate energy is as follows.

$P = I \times a$

where,

P = power or energy

I = intensity

a = area

Substitute the values into above formula as follows.

$P = I \times a\\= 1.11 \times 10^{-4} W/m^{2} \times 5.54 \times 10^{-5} m^{2}\\= 6.2 \times 10^{-9} W$

Thus, we can conclude that amount of energy transferred to each eardrum in one second is $6.2 \times 10^{-9} J$ .

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3 years ago

Fluid clutches are used on equipment that is subjected to?

mamaluj [8]

Fluid clutches are used on equipment that is subjected to higher torque per unit volume. This type of clutch makes use of an incompressible fluid like oil in order to transfer the input of a movement from a pedal and cylinder to an actuating cylinder. Releasing the this clutch would stop the transfer of power but still allowing the engine to turn continuously.

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3 years ago

What is the effect of gravity on a falling object?

Sedbober [7]

Answer:

gravity pulls the falling object to the ground

Explanation:

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3 years ago

State and apply the relation between electric force and electric field.

Olin [163]

Answer:

The following is the relation between electric force and field

$Electric Field = Electric Force / charge$

Explanation:

Electric force is the magnitude of electrostatic forces between two charges which is directly proportional to product of both charges and inversely proportional to the square of the distance between them.

$F=k*q1*q2/r^2$

Here k is the coulumb's constant.

Where as the electric field is the electric force per unit charge. It is the function of electric force. It is the vector quantity and its direction is taken radially inward or outward depending on the nature of charge.

Its equation is

Electric Field $E=F/q$

Electric Field units are in volts where as Electric force units are newtons.

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3 years ago