Weight = (mass) x (gravity)
Acceleration of gravity on Earth = 9.8 m/s²
Weight on Earth = (mass) x (9.8 m/s²)
Divide each side by (9.8 m/s²): Mass = (weight) / (9.8 m/s²)
Mass = (650 N) / (9.8 m/s²)
Mass = 66.33 kg (rounded)
Answer:
Option (D)
Explanation:
Wind erosion will take place extensively as the cliff-side is exposed on the outcrop. Due to the wind erosion, the large, jagged rock will undergo the process of weathering where the softer parts of the rock will be eroded much rapidly in comparison to the harder parts, as a result of which the overall size of the rock will decrease and the surface will be uneven and somewhat rough. This will take place over a due course of time. The main agent that is responsible for erosion is the wind.
Thus, the given rock will become smaller and less smooth after a definite period of time.
Thus, the correct answer is option (D).
<span>
The needle of a compass will always lies along the magnetic
field lines of the earth.
A magnetic declination at a point on the earth’s surface
equal to zero implies that
the horizontal component of the earth’s magnetic field line
at that specific point lies along
the line of the north-south magnetic poles. </span>
The presence of a
current-carrying wire creates an additional <span>
magnetic field that combines with the earth’s magnetic field.
Since magnetic
<span>fields are vector quantities, therefore the magnetic field of
the earth and the magnetic field of the vertical wire must be
combined vectorially. </span></span>
<span>
Where:</span>
B1 = magnetic field of
the earth along the x-axis = 0.45 × 10 ⁻ ⁴ T
B2 = magnetic field due to
the straight vertical wire along the y-axis
We can calculate for B2
using Amperes Law:
B2 = μ₀ i / [ 2 π R ]
B2 = [ 4π × 10 ⁻ ⁷ T • m / A ] ( 36 A ) / [ 2 π (0.21 m ) ] <span>
B2 = 5.97 × 10 ⁻ ⁵ T = 0.60 × 10 ⁻ ⁴ T </span>
The angle can be
calculated using tan function:<span>
tan θ = y / x = B₂ / B₁ = 0.60 × 10 ⁻ ⁴ T / 0.45 × 10 ⁻ ⁴ T <span>
tan θ = 1.326</span></span>
θ = 53°
<span>
<span>The compass needle points along the direction of 53° west of
north.</span></span>
