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kherson [118]
3 years ago
10

I really need help before tomorrow!! Please help me!!

Mathematics
2 answers:
Pavel [41]3 years ago
8 0

Answer:

the answer is 6

Step-by-step explanation:

you take the absolute value for both of them which is 2 and 8 but you keep the negative still so it would be -2+8 which is 6

Charra [1.4K]3 years ago
3 0

Answer:

6

Step-by-step explanation:

The absolute value of -2 is 2, but with the negative on the outside it would be -2.

Next the absolute value of -8 is 8.

Therefore 8+-2=6

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I don’t understand this at all
Lemur [1.5K]

9514 1404 393

Answer:

  9(x +y)

Step-by-step explanation:

You observe that both terms have a coefficient of 9. The distributive property lets you factor that out, so you can rewrite the expression as ...

  9x +9y = 9(x +y)

_____

It might help to think of parentheses as a "bag." The expression 9(x+y) tells you the contents of one bag is (x+y) and you have 9 of them. You could think of x, and y as representing two different physical objects, for example, perhaps a ball and a cube.

The first expression, 9x +9y, tells you that you have 9 of each of these objects. The distributive property says this could be the result of dumping the contents of 9 bags, each containing one each of the objects. The expression 9(x+y) is the version of the expression that shows these objects as being grouped into 9 bags.

3 0
3 years ago
Check all that apply. Thanks!
spayn [35]

Answer:

The answers are options C and E

Hope this helps you

8 0
3 years ago
Suppose a random variable x is best described by a uniform probability distribution with range 22 to 55. Find the value of a tha
const2013 [10]

Answer:

(a) The value of <em>a</em> is 53.35.

(b) The value of <em>a</em> is 38.17.

(c) The value of <em>a</em> is 26.95.

(d) The value of <em>a</em> is 25.63.

(e) The value of <em>a</em> is 12.06.

Step-by-step explanation:

The probability density function of <em>X</em> is:

f_{X}(x)=\frac{1}{55-22}=\frac{1}{33}

Here, 22 < X < 55.

(a)

Compute the value of <em>a</em> as follows:

P(X\leq a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.95\times 33=[x]^{a}_{22}\\\\31.35=a-22\\\\a=31.35+22\\\\a=53.35

Thus, the value of <em>a</em> is 53.35.

(b)

Compute the value of <em>a</em> as follows:

P(X< a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.49\times 33=[x]^{a}_{22}\\\\16.17=a-22\\\\a=16.17+22\\\\a=38.17

Thus, the value of <em>a</em> is 38.17.

(c)

Compute the value of <em>a</em> as follows:

P(X\geq  a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.85=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.85\times 33=[x]^{55}_{a}\\\\28.05=55-a\\\\a=55-28.05\\\\a=26.95

Thus, the value of <em>a</em> is 26.95.

(d)

Compute the value of <em>a</em> as follows:

P(X\geq  a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.89=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.89\times 33=[x]^{55}_{a}\\\\29.37=55-a\\\\a=55-29.37\\\\a=25.63

Thus, the value of <em>a</em> is 25.63.

(e)

Compute the value of <em>a</em> as follows:

P(1.83\leq X\leq  a)=\int\limits^{a}_{1.83} {\frac{1}{33}} \, dx \\\\0.31=\frac{1}{33}\cdot \int\limits^{a}_{1.83} {1} \, dx \\\\0.31\times 33=[x]^{a}_{1.83}\\\\10.23=a-1.83\\\\a=10.23+1.83\\\\a=12.06

Thus, the value of <em>a</em> is 12.06.

7 0
3 years ago
Please help I just need the height and area of the triangle 6th grade math
Vesna [10]

Answer:

It looks like you forgot to attach a picture.

Since I cannot answer you're question fully, it will not be a complete solution.

The formula for the area of a triangle is \frac{1}{2} b \cdot h.

Just substitute you're base and height values.

Hope this helps!!!

5 0
3 years ago
3721nm equals how many m
e-lub [12.9K]

Answer:

0.000003721m

Scientific Notation: 3.72*10^-6

Step-by-step explanation:

1nm is 1*10^-6nm

Based on that we find the answer above.

8 0
3 years ago
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