Question

Javon, Sam, and Antoine are baking cookies. Javon has 3/2 cup of flour, Sam has 4 1/3 cups of flour, and Antoine has 3 4/6 cups of flour. How many cups of flour do they have altogether?

Answer 1

Answer:

They have $9\frac{3}{6}\ cups$ of flour altogether.

Step-by-step explanation:

Given:

Amount of flour Javon has = $\frac{3}{2}\ cup$

Amount of flour Sam has = $4\frac{1}{3}\ cups$

$4\frac{1}{3}\ cups$ can be Rewritten as $\frac{13}{3}\ cups$

Amount of flour Sam has = $\frac{13}{3}\ cups$

Amount of flour Antoine has = $3\frac{4}{6}\ cups$

$3\frac{4}{6}\ cups$ can Rewritten as $\frac{22}{6}\ cups$

Amount of flour Antoine has = $\frac{22}{6}\ cups$

We need to find the amount of cups of flour they have altogether.

Solution:

Now we can say that;

the amount of cups of flour they have altogether can be calculated by sum of Amount of flour Javon has and Amount of flour Sam has and Amount of flour Antoine has.

framing in equation form we get;

amount of cups of flour they have altogether = $\frac{3}{2}+\frac{13}{3}+\frac{22}{6}$

Now to solve we need to make the denominator common by using L.C.M we get;

amount of cups of flour they have altogether = $\frac{3\times3}{2\times3}+\frac{13\times2}{3\times2}+\frac{22\times1}{6\times1}=\frac{9}{6}+\frac{26}{6}+\frac{22}{6}$

Now Denominators are common so we will add the numerators we get;

amount of cups of flour they have altogether = $\frac{9+26+22}{6}= \frac{57}{6}\ cups\ \ OR \ \ 9\frac{3}{6}\ cups$

Hence They have $9\frac{3}{6}\ cups$ of flour altogether.