"what is the value of a in the equation 81^b=a^4b"
1 answer:
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Answer:
- y = 6 at x = 5
Step-by-step explanation:
It is assumed the question is about finding the minimum value as the given function has no maximum value, it is + ∞ as the coefficient of x² is positive
<u>The minimum/maximum value of a quadratic function is the vertex, which is at:</u>
- x = -b/2a
<u>For the given function y = x² -10x + 31, the vertex is:</u>
- x = - (-10)/2*1 = 10/2 = 5
<u>The value of y at this point is:</u>
- y = 5² - 10*5 + 31 = 25 - 50 + 31 = 6
<u>The point is </u>
- (5, 6)
