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Anastasy [175]
3 years ago
8

what is the tax on a bicycle that costs 235.00 if the tax rate is 5%? what is the total cost of the bicycle

Mathematics
1 answer:
anyanavicka [17]3 years ago
6 0
235 + 0.05(235) = 235 + 11.75 = 246.75 <== total cost (with the 5% tax being 11.75)
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Mrs. Wong has placed together 60% of the pieces of a jigsaw puzzle She has placed 570 pieces of the puzzle together How many pie
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570/x = 60/100. 60% of the total amount of jigsaw puzzles is 570, we could use that information to form the equation above, where x is the total amount of pieces. The total amount of jigsaw puzzles is 950.
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3 years ago
While on vacation, a family of five rented a car to get them to all the places they wanted to see for five days. The car costs a
Sloan [31]

multiply 50x5=250 so its 250

4 0
3 years ago
6 2/3 miles ➕ 4 11/16 =
mihalych1998 [28]

Answer:Add up fractions. The answer is 11 17/48

Step-by-step explanation:

hope this helps!

8 0
4 years ago
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2<br> v<br> What is the equation of a line that is parallel to y = -4x – 3 and shifted down 3 units?
Ugo [173]

Answer: y=-4x-6

Step-by-step explanation:

Given

The equation of line is y=-4x-3

The line which is parallel to the given line is y=-4x+c

and shifted by 3 units down i.e. its y-intercept is 3 units below the given line

\therefore y=-4x-3-3\\\Rightarrow y=-4x-6

3 0
3 years ago
A company is interviewing potential employees. Suppose that each candidate is either qualified, or unqualified with given probab
stira [4]

Answer:

P(C=1|T=1)=q(\sum_{i=15}^{20}\binom{20}{i} p^i(1-p)^{20-i})( \sum_{i=15}^{20}\binom{20}{i}[qp^i(1-p)^{20-i} + (1-q)p^{20-i}(1-p)^i])^{-1}

Step-by-step explanation:

Hi!

Lets define:

C = 1  if candidate is qualified

C = 0 if candidate is not qualified

A = 1 correct answer

A = 0 wrong answer

T = 1 test passed

T = 0 test failed

We know that:

P(C=1)=q\\P(A=1 | C=1) = p\\P(A=0 | C=0) = p

The test consist of 20 questions. The answers are indpendent, then the number of correct answers X has a binomial distribution (conditional on the candidate qualification):

P(X=x | C=1)=f_1(x)=\binom{20}{x}p^x(1-p)^{20-x}\\P(X=x | C=0)=f_0(x)=\binom{20}{x}(1-p)^xp^{20-x}

The probability of at least 15 (P(T=1))correct answers is:

P(X\geq 15|C=1)=\sum_{i=15}^{20}f_1(i)\\P(X\geq 15|C=0)=\sum_{i=15}^{20}f_0(i)\\

We need to calculate the conditional probabiliy P(C=1 |T=1). We use Bayes theorem:

P(C=1|T=1)=\frac{P(T=1|C=1)P(C=1)}{P(T=1)}\\P(T=1) = qP(T=1|C=1) + (1-q)P(T=1|C=0)

P(T=1)=q\sum_{i=15}^{20}f_1(i) + (1-q)\sum_{i=15}^{20}f_0(i)\\P(T=1)=\sum_{i=15}^{20}\binom{20}{i}[qp^i(1-p)^{20-i} + (1-q)p^{20-i}(1-p)^i)]

P(C=1|T=1)=q(\sum_{i=15}^{20}\binom{20}{i} p^i(1-p)^{20-i})( \sum_{i=15}^{20}\binom{20}{i}[qp^i(1-p)^{20-i} + (1-q)p^{20-i}(1-p)^i])^{-1}

5 0
3 years ago
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