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VashaNatasha [74]
3 years ago
7

A rectangle with vertices A(6, 0), K(0,0), L(0,9), and M(6, 9) is rotated around the x-axis. To the nearest tenth of a cubic uni

t, what is the volume of the resulting three-dimensional figure? Approximate as 3.14.
Mathematics
1 answer:
koban [17]3 years ago
7 0

Answer:

1526.0 cubic units

Step-by-step explanation:

Rotating rectangle AKLM you will get cylinder with height KA and base radius KL.  From the given data

KA=\sqrt{(6-0)^2+(0-0)^2}=6,\\ \\KL=\sqrt{(0-0)^2+(9-0)^2}=9.

The volume of the cylinder is

V_{cylinder}=\pi r^2\cdot H.

Then

V_{cylinder}=\pi \cdot 9^2\cdot 6=486\pi \approx 1526.0\ un^3.

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If the first and the last term of an arithmetic progression, with common difference
devlian [24]

The number of terms in the given arithmetic sequence is n = 10. Using the given first, last term, and the common difference of the arithmetic sequence, the required value is calculated.

<h3>What is the nth term of an arithmetic sequence?</h3>

The general form of the nth term of an arithmetic sequence is

an = a1 + (n - 1)d

Where,

a1 - first term

n - number of terms in the sequence

d - the common difference

<h3>Calculation:</h3>

The given sequence is an arithmetic sequence.

First term a1 = 1\frac{1}{2} = 3/2

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Common difference d = 1/9

From the general formula,

an = a1 + (n - 1)d

On substituting,

5/2 = 3/2 + (n - 1)1/9

⇒ (n - 1)1/9 = 5/2 - 3/2

⇒ (n - 1)1/9 = 1

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∴ n = 10

Thus, there are 10 terms in the given arithmetic sequence.

learn more about the arithmetic sequence here:

brainly.com/question/503167

#SPJ1

Disclaimer: The given question in the portal is incorrect. Here is the correct question.

Question: If the first and the last term of an arithmetic progression with a common difference are 1\frac{1}{2}, 2\frac{1}{2} and 1/9 respectively, how many terms has the sequence?

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2 years ago
2 Points
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Answer: A

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(f+g)(x) means f(x)+g(x). Since we are given f(x) and g(x), we cna add them together.

x+8+(-4x-3)

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