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xenn [34]
3 years ago
6

Suppose that the function g is defined for all real numbers as follows

Mathematics
1 answer:
Talja [164]3 years ago
3 0

Answer:

-9

0

3

Step-by-step explanation:

-(-2-1)^2

-(1-1)^2

x>2 , so g(x) = 3

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An individual repeatedly attempts to pass a driving test. Suppose that the probability of passing the test with each attempt is
vladimir1956 [14]

Answer:

a) Our random variable X="number of tests taken until the individual passes" follows a geomteric distribution with probability of success p=0.25

For this case the probability mass function would be given by:

P(X= k) = (1-p)^{k-1} p , k = 1,2,3,...

b) P(X \leq 3) = P(X=1) +P(X=2) +P(X=3)

P(X= 1) = (1-0.25)^{1-1} *0.25 = 0.25

P(X= 2) = (1-0.25)^{2-1} *0.25 = 0.1875

P(X= 3) = (1-0.25)^{3-1} *0.25 = 0.1406

And adding the values we got:

P(X \leq 3) =0.25+0.1875+0.1406=0.578

c) P(X \geq 5) = 1-P(X

And we can find the individual probabilities:

P(X= 1) = (1-0.25)^{1-1} *0.25 = 0.25

P(X= 2) = (1-0.25)^{2-1} *0.25 = 0.1875

P(X= 3) = (1-0.25)^{3-1} *0.25 = 0.1406

P(X= 4) = (1-0.25)^{4-1} *0.25 = 0.1055

P(X \geq 5) = 1-[0.25+0.1875+0.1406+0.1055]= 0.316

Step-by-step explanation:

Previous concepts

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

P(X=x)=(1-p)^{x-1} p

Let X the random variable that measures the number of trials until the first success, we know that X follows this distribution:

X\sim Geo (1-p)

Part a

Our random variable X="number of tests taken until the individual passes" follows a geomteric distribution with probability of success p=0.25

For this case the probability mass function would be given by:

P(X= k) = (1-p)^{k-1} p , k = 1,2,3,...

Part b

We want this probability:

P(X \leq 3) = P(X=1) +P(X=2) +P(X=3)

We find the individual probabilities like this:

P(X= 1) = (1-0.25)^{1-1} *0.25 = 0.25

P(X= 2) = (1-0.25)^{2-1} *0.25 = 0.1875

P(X= 3) = (1-0.25)^{3-1} *0.25 = 0.1406

And adding the values we got:

P(X \leq 3) =0.25+0.1875+0.1406=0.578

Part c

For this case we want this probability:

P(X \geq 5)

And we can use the complement rule like this:

P(X \geq 5) = 1-P(X

And we can find the individual probabilities:

P(X= 1) = (1-0.25)^{1-1} *0.25 = 0.25

P(X= 2) = (1-0.25)^{2-1} *0.25 = 0.1875

P(X= 3) = (1-0.25)^{3-1} *0.25 = 0.1406

P(X= 4) = (1-0.25)^{4-1} *0.25 = 0.1055

P(X \geq 5) = 1-[0.25+0.1875+0.1406+0.1055]= 0.316

3 0
3 years ago
HELP!!!!!plz!!!!!!ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Ugo [173]
Is it not 2? or half?
8 0
3 years ago
What is the reciprocal
weqwewe [10]
Answer is C. 7/12 has the reciprocal of 12/7. When You multiply by a reciprocal, you just switch the numerator and denominator. The answer does NOT become negative. It would change the fraction itself.
Example:
3/6= 6/3
5/7= 7/5
3 0
3 years ago
Read 2 more answers
How many can 8 go in to 18
Zinaida [17]

Answer:

8 can go into eighteen 2.25 times

3 0
3 years ago
Read 2 more answers
Pls help i will give brainliest
kirill [66]

Answer:

1) 2

2) -2

Step-by-step explanation:

1)

x - 5 = -3

Add 5 to both sides

x = 2

2)

3 - 2x = x + 9

Add 2x to both sides.

3 = 3x + 9

Subtract 9 from both sides

-6 = 3x

Divide both sides by 3

-2 = x

x = -2

Hope this helps you understand! :D

8 0
2 years ago
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