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The completely factored form of 4x^2 + 28x + 49 is given by: Option C: (2x+7)(2x+7)
<h3>How to find the factors of a quadratic expression?</h3>If the given quadratic expression is of the form ax^2 + bx + c, then its factored form is obtained by two numbers alpha( α ) and beta( β) such that:
Then writing b in terms of alpha and beta would help us getting common factors out.
Sometimes, it is not possible to find factors easily, so using the quadratic equation formula can help out without any trial and error.
For this case, the given quadratic expression is:
So we've to find two numbers such that:
Their sum = b = 28
Their product =
We can see that 196 is square of 14, and that 14 added twice forms 28, thus:
14 + 14 = 28
14×14 = 196
Writing b = 28 as sum of 14 twice, we get:
Thus, the completely factored form of 4x^2 + 28x + 49 is given by: Option C: (2x+7)(2x+7)
Learn more about factorization of quadratic expression here:
we know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form y/x=k or y=kx
so
That means it's the equation of a line passing through the origin.
case a) and case d) are discarded because the line does not pass through the origin
<u>case b) we have</u>
for x=2 y=4
y/x=k-------> 4/2=2------> k=2
y=2x-------> in this case the value of y is two times the value of x
<u>case c) we have</u>
for x=4 y=2
y/x=k-------> 2/4=1/2------> k=(1/2)
y=(1/2)x-------> in this case the value of y is one-half of the value of x
therefore
the solution is the case c) see the attached figure
