All categories

3 years ago

A 1.0 l buffer solution is 0.10 m in hf and 0.050 m in naf. which action destroys the buffer?

1 answer:

7 0

A buffer is a useful chemical in science that is composed of a weak acid and salt. From the given compounds above, between HF and NaF, HF is a strong acid and NaF is a salt. Thus, addition of HF will most likely destroy the buffer.

You might be interested in

18 feet long and 12 feet wide. What is the area of the floor in square yards?

forsale [732]

Area of a rectangle =length*width

length=18ft=18/3=6yds
width=12ft=12/3=4yds

answer: $A=6*4= 24 yds^{2}$

3 0

3 years ago

Read 2 more answers

Evaluate v(x) = 12 - 2x - 5 when x = -2,0. and 5.

EleoNora [17]

Answer:

11,7,-3 respectively

Step-by-step explanation:

when x is -2 ,0 and 5 the result will be 11, 7 and -3 respectively

4 0

3 years ago

Determine the vertex of the function f(x) = 3(x − 2)2 + 1.

anastassius [24]

The vertex point of the function f(x) = 3(x - 2)² + 1 is (2 , 1) ⇒ answer A

Step-by-step explanation:

Any quadratic function represented graphically by a parabola

1. If the coefficient of x² is positive, then the parabola open upward

and its vertex is a minimum point

2. If the coefficient of x² is negative, then the parabola open

downward and its vertex is a maximum point

3. The standard form of the quadratic function is: f(x) = ax² + bx + c

where a, b , c are constants

4. The vertex form of the quadratic function is: f(x) = a(x - h)² + k,

where h , k are the coordinates of its vertex point

∵ The function f(x) = 3(x - 2)² + 1

∵ The f(x) = a(x - h)² + k in the vertex form

∴ a = 3 , h = 2 , k = 1

∵ h , k are the coordinates of the vertex point

∴ The coordinates of the vertex point are (2 , 1)

The vertex point of the function f(x) = 3(x - 2)² + 1 is (2 , 1)

Learn more:

You can learn more about quadratic function in brainly.com/question/1357167

#LearnwithBrainly

6 0

3 years ago

Read 2 more answers

Drop ur ig/ t i k t o k :)))

kobusy [5.1K]

Answer:

lance

Step-by-step explanation:

uwuuu!!

thanks for the points

6 0

2 years ago

Arrange the equations in the correct sequence to rewrite the formula for displacement, , to find a. In this formula, d is displa

valina [46]

Answer:

$a=2[d-V_0t]/t^2=2d/t^2-2v_0/t$

Explanation:

Since, you have not included the formula, I will work here with the formula for constant accelaration motion that relates the four variables: displacement (d), Vo (initial velocity), a (acceleration) and t (time).

1) displacement formula:

$d= V_0t+\frac{1}{2} at^2$

2) Subtract the term Vot from both sides:

$d-V_0t= \frac{1}{2} at^2$

3) Multiply both sides by 2:

$2d -2V_0t=at^2$

4) Divide both sides by t²

$2[d-V_0t]/t^2=a$

So, you have obtainded:

a = 2[d - Vo×t] / t²

Yet, you can arrange it in different ways. For example, you might separate into two terms:

$a = \frac{2d}{t^2} - \frac{2V_0}{t}$

8 0

3 years ago